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vesna_86 [32]
2 years ago
12

Segment AB is congruent to segment AB.t h s statement shows the ______ property.

Mathematics
1 answer:
trapecia [35]2 years ago
8 0
Distributive property
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in how many ways can a supermarket chain select 3 out of 12 possible sites for construction of a new supermarket?
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Answer:

its 220

Step-by-step explanation:

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3 years ago
Jared wrote an equation for the perimeter of an equilateral triangle as 3x = 20. What does x represent in his equation?
ratelena [41]
The perimeter of an object is equal to its sides added up.  Because this is a triangle, it will have 3 equal sides.  Since the triangle has 3 equal sides, its perimeter will be equal to one of its side lengths * 3.  

Because the perimeter will be equal to one of its side lengths * 3, x is equal to one of the triangle's side lengths.
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3 years ago
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Which expression is equivalent? Please see pictures attached!
VMariaS [17]

hey, u didn’t rlly attach anything :/

5 0
3 years ago
2. A printing machine makes 240 books
Marizza181 [45]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 8 books/ hour

Explanation:

240 / 30 = 8 books/ hour

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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7 0
3 years ago
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4. Gloria the grasshopper is working on her hops.
aivan3 [116]

The path that Gloria follows when she jumped is a path of parabola.

The equation of the parabola  that describes the path of her jump is \mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

The given parameters are:

\mathbf{Height = 20}

\mathbf{Length = 28}

<em>Assume she starts from the origin (0,0)</em>

The midpoint would be:

\mathbf{Mid = \frac 12 \times Length}

\mathbf{Mid = \frac 12 \times 28}

\mathbf{Mid = 14}

So, the vertex of the parabola is:

\mathbf{Vertex = (Mid,Height)}

Express properly as:

\mathbf{(h,k) = (14,20)}

A point on the graph would be:

\mathbf{(x,y) = (28,0)}

The equation of a parabola is calculated using:

\mathbf{y = a(x - h)^2 + k}

Substitute \mathbf{(h,k) = (14,20)} in \mathbf{y = a(x - h)^2 + k}

\mathbf{y = a(x - 14)^2 + 20}

Substitute \mathbf{(x,y) = (28,0)} in \mathbf{y = a(x - 14)^2 + 20}

\mathbf{0 = a(28 - 14)^2 + 20}

\mathbf{0 = a(14)^2 + 20}

Collect like terms

\mathbf{a(14)^2 =- 20}

Solve for a

\mathbf{a =- \frac{20}{14^2}}

\mathbf{a =- \frac{20}{196}}

Simplify

\mathbf{a =- \frac{5}{49}}

Substitute \mathbf{a =- \frac{5}{49}} in \mathbf{y = a(x - 14)^2 + 20}

\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

Hence, the equation of the parabola  that describes the path of her jump is \mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

See attachment for the graph

Read more about equations of parabola at:

brainly.com/question/4074088

7 0
2 years ago
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