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Alik [6]
3 years ago
14

W is greater than 5 and less than or equal to 9 Use w only once in your inequality.

Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

5<w<=9

Step-by-step explanation:

hope this helps good luck

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Function 1 is defined by the equation y=-1/4r-5<br> Function 2
steposvetlana [31]

Step-by-step explanation:

as just answered in the other question, the y-intercept is simply the y-value, when x=0.

it is -5 for function 1.

and function 2 clearly crosses the y-axis at y = -7, which is the y-intercept.

as -5 is greater than -7, function 1 had the greater y- intercept.

3 0
2 years ago
What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?
BlackZzzverrR [31]
3^5) (x + 2)^(3/2) + 3 = 27 
<span>(x + 2)^(3/2) = 24 / 243 </span>
<span>x + 2 = [ 24 / 243 ]^(2/3) </span>
<span>x + 2 = [ 8 / 81 ]^(2/3) </span>
<span>x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786</span>
4 0
3 years ago
Read 2 more answers
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

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\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
A six-sided number cube is rolled, and then a spinner with 5 equal sections labeled A through E is spun.
natka813 [3]
16 I think if not 130
4 0
2 years ago
Read 2 more answers
Help me please ! Thank you so so much :)
notka56 [123]
#4 = B
Explanation= Because C&A are the same angle measurement, and the 90 angle is along a straight line making the other angle 90, and the triangles share the same side the postulate you can use is AAS because you can prove that the triangles share 2 common angles and 1 common side

#5 = B
Explanation= Because the triangles already have 1 congruent angle, and 1 congruent side the only thing left we can prove is that because the triangles mirror each other, they have congruent opposite angles (may be called vertical angles) as well so they have 2 angles and 1 side in common which tells you to use AAS
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3 years ago
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