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Lerok [7]
1 year ago
10

Help me please show your solution ​

Mathematics
1 answer:
m_a_m_a [10]1 year ago
5 0

Answer:

Rule: Multiplying ×5 in turn

50 { third term}

1,250 {fifth term}

Step-by-step explanation:

2 × 5 = 10 {second term}

10 × 5 = 50 { third term}

50 × 5 = 250 { fourth term}

250 × 5 = 1,250 {fifth term}

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Factorise <br> a) 4p²-81<br> b) x²-13x+36
taurus [48]

Answer:

A = (2p + 9) (2p - 9)

B = (x - 9) (x - 4)

Step-by-step explanation:

For A : Rewrite 4p^2 as (2p)^2.

(2p)^2−81

Rewrite 81 as 9^2.

(2p)^2−9^2

Since both terms are perfect squares, factor using the difference of squares formula, a^2 − b^2 = ( a + b ) ( a − b ) where a = 2p and b = 9 .

(2p + 9) (2p − 9)

For B : Consider the form x^2 + bx + c . Find a pair of integers whose product is c and whose sum is b . In this case, whose product is 36 and whose sum is − 13 .

-9, -4

(x - 9) (x - 4)

I hope this helps.

7 0
3 years ago
Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point) a 2 b 3 c All real numbers d No solution
Fofino [41]

-2(x + 3) = -2(x + 1) - 4

-2x - 6 = -2x - 2 - 4        <em>distributed -2 on the left and on the right</em>

-2x - 6 = -2x - 6

<u>+2x     </u>   <u>+2x      </u>

     -6 =        -6

        TRUE

Since this is a true statement, there are infinite solutions (aka All Real Numbers)

Answer: C

8 0
3 years ago
8th grade math probability
kari74 [83]
In problem 16 I think the answers is b
3 0
2 years ago
Mrs. thomas has 18 cups of popcorn. she wanted to divide the popcorn into 2/3 cup bags.how many bags can she make ?
Usimov [2.4K]
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3 0
3 years ago
which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
victus00 [196]
One equation for this would be

y = \frac{41}{16} x-\frac{55}{8}

We start by finding the slope between the two points:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}&#10;\\&#10;\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})&#10;\\&#10;\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})&#10;\\&#10;\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}

A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)&#10;\\&#10;\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{550}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{55}{8}
6 0
3 years ago
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