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vodomira [7]
3 years ago
13

The rules of a contest say that there is a 5% chance of winning a prize. 400 people enter the contest. Predict how many people w

ill win a prize.​
Mathematics
2 answers:
Nataly [62]3 years ago
8 0

Answer:

20 people

Step-by-step explanation:

In this problem, you are solving for 5% of 400. All percentages are out of 100, meaning 5% equals 0.05 because 5 ÷ 100 = 0.05

1. Multiply 400 by 5% (0.05)

400 · 0.05 = 20 people

RUDIKE [14]3 years ago
8 0

Answer:

20 people will win

Step-by-step explanation:

i used a notes and google to answer this :)

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27.69

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What shape has<br> 4 equal sides and<br> No right angles
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Rhombus

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Find the distance between the points L and D.<br><br>A)-2<br>B)0<br>C)1<br>D)2​
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8 0
3 years ago
How many 3/4 cup servings are in 12 cups of cherries?
AveGali [126]

Answer:

16 serving.

Step-by-step explanation:

Given: 3/4 cup servings.

Now, computing the number of serving in 12 cups of cherries.

Using unitary method to solve.

∴ Number of serving= total\ cups \times number\ of\ serving\ per\ cup

Number of serving in one cup is \frac{4}{3}

Number of serving in 12 cups = 12\times \frac{4}{3} = 16 \ serving

Number of serving in 12 cups= 16\ serving

∴ There are 16 serving is possible in 12 cups of cherries.

8 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
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