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Rufina [12.5K]
3 years ago
5

How smart are you? a woman walks into a store and steals a $100

Mathematics
1 answer:
Alex3 years ago
7 0
Um I don't get it can you be more Pacific please


I think it's -$100
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What is the area of the face marked f
Annette [7]

Answer:

12cm ...........

........

5 0
3 years ago
An accountant invested $5000 at a simple interest rate of 8% for 2 years. What total amount of money will she have from her inve
il63 [147K]

Answer:

$5800 plz give the brainliest

Step-by-step explanation:

you have to muliyiply everything so 5000*.08*2 which is 800 now add that to 5000 because thats the amount she put in so it will be $5800.

6 0
3 years ago
I just need help with this table
Mashutka [201]

Answer:

from the looks of it, all you have to do is, for f(x), is plug it in as an exponent. in order (top to bottom), it should be: 64, 2048, 4096, 8192.

g(x) is being squared and then multiplied, so it should be (from top to bottom): 720, 2420, 2880, 3380

Step-by-step explanation:

6 0
3 years ago
A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m
lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

F = 6N, e = 3m

K = 6N/3m

K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0
3 years ago
For each explicitly-defined sequence below, write the first few terms. Then use the terms to write a recursive equation.
julia-pushkina [17]

Answer:

Step-by-step explanation:

Problem A

t(1) = 2(1) + 5

t(2) = 2*2 + 5 = 9

t(3) = 2*3 + 5 = 11

t(4) = 2*4 + 5 = 13

So this is the explicit result. Now try it recursively.

t_3 = t_2 + 2

t_3 = 9 + 2

t_3 = 11          which is just what it should do.

t_n = t_(n - 1) + 2

Problem B

t(1) = 3 * 1/2

t(1) = 3/2

t(2) = 3*(1/2)^2

t(2) = 3 * 1/4

t(2) = 3/4

t(3) = 3*(1/2)^3

t(3) = 3 * 1/8

t(3) = 3/8

t(4) = 3 (1/2)^4

t(4) = 3 (1/16)

t(4) = 3/16

So in general

t_n = t_n-1 * 1/2

For example t(5)

t_5 = t_4 * 1/2

t_5 = 3 /16 * 1/2 = 3/32

6 0
3 years ago
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