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WINSTONCH [101]
3 years ago
13

The follow through is where you "pause" and hold the bow still for a few seconds after releasing the arrow.

Mathematics
1 answer:
timurjin [86]3 years ago
3 0

True-... i think because like i am not sure-

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Help Asap
Valentin [98]

Answer:

please try sending a photo so it would make more sense

8 0
3 years ago
I need help solving 4×-3(×2)=21
Lelechka [254]
My Mom did the work. The answer came out as X= 4.

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In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a
Sphinxa [80]

Answer:

\frac{2}{5}

Step-by-step explanation:

3 envelopes having 2 red card

2 envelopes having 1 red card and 1 black card

1 envelope having 2 black cards

We are given that . An envelope is selected at random and a card is withdrawn and found to be red.

So, No. of ways of envelope having red card = 3+2 = 5

No. of required ways of envelope having 1 red card and 1 black card = 2

So, probability of getting an envelope having 1 red card and 1 black card = \frac{2}{5}

Hence The chance the other card is black is \frac{2}{5}

5 0
3 years ago
What will be the perimeter and the area of the rectangle below if it is enlarged using a scale factor of 3.5? (1 point)
Anna11 [10]

Answer:

2. Perimeter = 98 cm, área = 588 cm²

5 0
3 years ago
PLLLLSSSSSSS HELP ME !!!!!!!???????
LenaWriter [7]

Answer:

Step-by-step explanation:

because -3 is a zero, so x=-3

(k-1)(-3)²+k(-3)+1=0

9(k-1)-3k+1=0

9k-9-3k+1=0

6k=8

3k=4

k=4/3

(B)

∵ x=-1 is a zero of p(x)=kx²-4x+k

so k(-1)²-4(-1)+(-1)=0

k+4-1=0

k=-3

7 0
3 years ago
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