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Serjik [45]
3 years ago
9

The where sells bagels zero $.75 each the bagel shop sells one dozen for seven dollars which is the better buy

Mathematics
1 answer:
Flura [38]3 years ago
8 0
12 bagels for $.75 is 9 dollars so buying a dozen for 7 dollars is better ☺️
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You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 1/6 minutes to set up the
igomit [66]

Answer:

B.

Step-by-step explanation:

Given,

The time for set up the game =  5\frac{1}{6} minutes,  

Also, the time for each level of game is 7\frac{1}{3\\} minutes,  

If there are l levels of games,  

Then the time taken in all levels of game = (7\frac{1}{3}) l<em> </em>

Hence, the total time ( in minutes ) = Set up time + time in all level

= 5\frac{1}{6} +(7\frac{1}{3}) l

We have 60-minute of free trial of the game,

So, the total time taken can not be exceed to 60 minutes,

= 5\frac{1}{6} +(7\frac{1}{3}) l\leq 60

Which is the required inequality.  

Option 'B' is correct.

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm
Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so

-3x^{2*4} y^{1*4}

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well  and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

81x^{8}y^{4}

5 0
3 years ago
Read 2 more answers
I NEED UR HELPFNGKFNKFJFF
alisha [4.7K]

For Q3, you can subsitute x = 2 and y = 5 into the systems

-5(2) + 5 = -5

so it's a solution for the first system

-4(2)+2(5) = 2

it's also a solution for the second system

8 0
2 years ago
Which table represents the graph of a logarithmic function in the form y=log3x when b&gt;1?
alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u>y = log_{b} (x)<u><em></em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function y = log_{b} (x)   if b >1

Given first table

i)

put x = \frac{1}{8}     given b > 1 so we can choose b = 2

y = log_{2} (\frac{1}{8} )

y = log_{2} (2^{-3}  )

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-3}  ) = -3 log_{2} (2) = -3 (1) = -3

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em>\frac{1}{4}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{4} )<em></em>

<em></em>y = log_{2} (2^{-2}  )<em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-2}  ) = -2 log_{2} (2) = -2 (1) = -2

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em>\frac{1}{2}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{2} )<em></em>

y = log_{2} (2^{-1}  )

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

y = log_{2} (2^{-1}  ) = -1 log_{2} (2) = - (1) = -1

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (1 )<em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em>2<em>     given b > 1 so we can choose b = 2</em>

y = log_{2} (2 )

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

8 0
3 years ago
Read 2 more answers
Pleaseee helppp I don't understand thissd
Bess [88]

Very simple.

Let's say you have an equation.

f(x) = x^2

You are asked to find the value for y when x equals 1.

The new equation is: f(1) = (1)^2

f(1) = 1

When x = 1, y = 1.

The same concept is applied here.

In the graph, where does x equal 0?

It equals zero at the origin.

Is there any y-value associated with 0?

Yes, there is.

Y equals five when x equals 0.

So

h(0) = 5

6 0
3 years ago
Read 2 more answers
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