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egoroff_w [7]
3 years ago
15

Describing the square root of 0.6 which is less than one

Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

0.77 and -0.77

Step-by-step explanation:

just squareroot it

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Step-by-step explanation:

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What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star
Komok [63]

The quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

q=\dfrac{a}{b}

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

\dfrac{7^{-1}}{7^{-2}}

Let the quotient of this division is n. Therefore,

n=\dfrac{7^{-1}}{7^{-2}}

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

n=\dfrac{7^{2}}{7^{1}}\\n=7

Hence, the quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

Learn more about the quotient here;

brainly.com/question/673545

7 0
3 years ago
Y = x² +1,x&gt;0 <br> find the inverse
Greeley [361]

Answer:

The inverse of x² +1 is:  

\sqrt{x-1},\:-\sqrt{x-1}

Step-by-step explanation:

Given

y = x² + 1,  x>0

We know that A function g is the inverse of a function f if for y = f(x), x = g(y)

y = x² +1

Replace x with y

x = y² + 1

solve for y

y² = x - 1

Taking square root

y=\:\sqrt{x-1},-\sqrt{x-1}

Thus, the inverse of x² +1 is:  

\sqrt{x-1},\:-\sqrt{x-1}

7 0
3 years ago
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