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Ronch [10]
3 years ago
9

Let f(x) be the probability density function for the lifetime of a manufacturer's highest quality car tire, where x is measured

in miles. Explain the meaning of each integral. (a) 50,000 f(x) dx 40,000 The integral is the probability that a randomly chosen tire will have a lifetime under 50,000 miles. The integral is the probability that a randomly chosen tire will have a lifetime of exactly 50,000 miles. The integral is the probability that a randomly chosen tire will have a lifetime of at least 40,000 miles. The integral is the probability that a randomly chosen tire will have a lifetime between 40,000 and 50,000 miles.
Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

(a) The integral in total indicates the probability of a randomly selected tire having a lifetime between 40,000 miles to 50,000 miles.

(b) The integral in total indicates the probability of a randomly selected tire having a lifetime of at least 25,000 miles.

Step-by-step explanation:

The probability density function for the lifetime of a manufacturer's highest quality car tire is denoted by, <em>f </em>(<em>x</em>).

(a)

The integral given is:

\int\limits^{50,000}_{40,000} {f(x)}\, dx

The values 40,000 and 50,000 indicates the limits of the integral.

It implies that the integral is to be solved over the range (40,000 - 50,000) miles.

And the integral in total indicates the probability of a randomly selected tire having a lifetime between 40,000 miles to 50,000 miles.

(b)

The integral given is:

\int\limits^{\infty}_{25,000} {f(x)}\, dx

The values 25,000 and ∞ indicates the limits of the integral.

It implies that the integral is to be solved over the range (25,000 - ∞) miles.

And the integral in total indicates the probability of a randomly selected tire having a lifetime of at least 25,000 miles.

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IF YOU CAN ANSWER CORRECTLY I WILL MARK YOU BRAINLIEST
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Answer:

1,436.75 cubic millimeters

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1,436 cubic millimeters

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}&#10;\textit{circumference of a circle}\\\\ &#10;2\pi r&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{arc's length}\\\\&#10;s=\cfrac{\theta r\pi }{180}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+&#10;\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}&#10;\\\\\\&#10;15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}&#10;\textit{area of a circle}\\\\ &#10;\pi r^2&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{area of a sector of a circle}\\\\&#10;s=\cfrac{\theta r^2\pi }{360}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}&#10;\\\\\\&#10;90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

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4 years ago
I need help completing this answer are you available
melomori [17]

Answer:

Step-by-step explanation:

7 0
3 years ago
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