Consecutive numbers would be like 2 and 3, or 7 and 8.
All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.
1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>
</em>
AG and GB must be congruent and CG and GD must be congruent as well
Answer:
A' will be located 10 units from point A along ray PA
Step-by-step explanation:
we know that
The scale factor is equal to 3
To obtain PA', multiply PA by the scale factor
so
PA'=PA*3
PA=5 units
substitute
PA'=(5)*3=15 units
AA'=PA'-PA=15-5=10 units
therefore
A' will be located 10 units from point A along ray PA
Answer:
4.8
Step-by-step explanation:
![r = \sqrt[3]{108} \\ \\ r = 4.7622031559 \\ \\ r \approx \: 4.8 \:](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B108%7D%20%20%5C%5C%20%20%5C%5C%20r%20%3D%204.7622031559%20%5C%5C%20%20%5C%5C%20r%20%5Capprox%20%5C%3A%204.8%20%5C%3A%20)
The answer is b foo im pretty sure
