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3 years ago

What is the value of 6/x + 2x2, when x = 3?

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Replace x = 3 into <span>6/x + 2x^2

</span>6/x + 2x^2

=6/3 + 2 (3)^2
= 2 + 2(9)
= 2 + 18
= 20

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8x –3(5x–2)=7–10x <br><br> Solve this equation with a clear value for x

Serga [27]

Answer:

x = 1/3

Step-by-step explanation:

8x –3(5x–2)=7–10x

Distribute

8x - 15x +6 = 7-10x

Combine like terms

-7x + 6 = 7- 10x

Add 10x to each side

-7x +10x+ 6 = 7- 10x+10x

3x+6 = 7

Subtract 6 from each side

3x+6-6 =7-6

3x = 1

Divide each side by 3

3x/3 = 1/3

x = 1/3

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Answer:

$y=\frac{5}{7}x$ and $y=\frac{7}{9}x$

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In $y=\frac{5}{7}x$ when x=3, y=15/4≈2.14

In $y=\frac{3}{5}x$ when x=3, y=1.8

In $y=\frac{7}{9}x$ when x=3, y≈2.33

In $y=\frac{7}{11}x$ when x=3, y≈1.90

We can observe that in two cases, $y=\frac{5}{7}x$ and $y=\frac{7}{9}x$ , y is greater than 2.

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