So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
Answer:
The probability that the result is positive is P=0.04475=4.475%.
Step-by-step explanation:
We have the events:
D: disease present
ND: disease not present
P: test positive
F: test false
Then, the information we have is:
P(D)=0.005
P(P | D)=0.99
P(P | ND)=0.04
The total amount of positive test are the sum of the positive when the disease is present and the false positives (positive tests when the disease is not present).
The probability that the result is positive is P=0.04475.
Answer:
yque ha haceqr ailluey
Step-by-step explanation:
Answer:
The expected net winnings for the bet are -$1.0526
Step-by-step explanation:
P(x =+$20) = P(Black outcome) = 18/38
P(x =-$20) = P(red outcome) + P(green outcome)
= 18/38 + 2/38 = 20/38
Hence the probability distribution of x = $20 , P(x) = 18/38
x = -$20, P(x) = 20/38
Expected value of the random variable x is given by ;
miu = Summation [xP(x)] = 20(18/38) - 20( 20/38)
= -$1.0526
hence, the expected net winnings for the bet are -$1.0526
This implies that if a player bet on a very large number of games, the player would on the average lose $1.0526 per single bet
2x^2+7x-5+(-8x^2-3x+5)=-6x^2+4x.
