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mixas84 [53]
3 years ago
8

What is the median of the following set of numbers? 33, 30, 29, 28, 27, 34, 31

Mathematics
2 answers:
kodGreya [7K]3 years ago
5 0
No the median is 30. 
IrinaVladis [17]3 years ago
4 0
Median is a middle value
So it is 28
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What is the solution set of {x | x < 2} {x | x ≥ 2}?
elena-14-01-66 [18.8K]

Answer:

I'm pretty sure it's B

Step-by-step explanation:

5 0
3 years ago
What is 73590 rounded to the nearest 10000?
Korolek [52]
It would round to 70,000
5 0
3 years ago
32% of 1600 = 512
yaroslaw [1]

Answer:

  • 64%: 1024
  • 96%: 1536
  • 132%: 2112
  • 232%: 3712

Step-by-step explanation:

<u>64% of 1600</u>

  64% of 1600 = 2 × (32% of 1600) = 2×512

  64% of 1600 = 1024

<u>96% of 1600</u>

  96% of 1600 = 3 × (32% of 1600) = 3×512

  96% of 1600 = 1536

<u>132% of 1600</u>

  132% of 1600 = (100% of 1600) + (32% of 1600) = 1600 + 512

  132% of 1600 = 2112

<u>232% of 1600</u>

  232% of 1600 = (100% of 1600) + (132% of 1600) = 1600 +2112

  232% of 1600 = 3712

3 0
3 years ago
Read 2 more answers
Marcela is registering for her college classes, which cost $105 per unit. How many units can she take to have a maximum cost of
OverLord2011 [107]

Answer:

Marcela can take up to 13 units.  

Step-by-step explanation:

In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable.  Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units.  The number of units multiplied by the cost per unit, must be less than or equal to $1,365.  In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105.  1365÷105 = 13.  So, the number of units that Marcela can take must be less than or equal to 13 units.  

6 0
2 years ago
Read 2 more answers
Find the average rate of change for f(x) = x2 + 9x + 18 from x = −10 to x = 10. A) 3 B) 7 C) 9 D) 11
Sergeeva-Olga [200]

Answer:

C

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 10, 10 ], thus

f(b) = f(10) = 10² + 9(10) + 18 = 100 + 90 + 18 = 208

f(a) = f(- 10) = (- 10)² + 9(- 10) + 18 = 100 - 90 + 18 = 28, thus

average rate of change = \frac{208-28}{10-(-10)} = \frac{180}{20} = 9

3 0
3 years ago
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