Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle = 


Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
Answer:
y=-3x-12
Step-by-step explanation:
Plug into equation y=mx+b
3=(-3)-5+b
Simplify
3=15+b
Subtract 15 from both sides
-12=b
Add slope and y-intercept into base equation
y=-3x-12
Answer:
4c - 2
Step-by-step explanation:
Add up all the terms to find the perimeter.
2c + 2(c - 1)
2c + 2c - 2
4c - 2
Therefore, the perimeter is 4c - 2.
Lcm= 2
Because
2/2= 1
2/8=4
2/10=5