All categories

3 years ago

If the clock runs slow and loses 15 s per day, how should you adjust the length of the pendulum?

Physics

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

L= 1 m, ΔL = 0.0074 m

Explanation:

A clock is a simple pendulum with angular velocity

w = √ g / L

Angular velocity is related to frequency and period.

w = 2π f = 2π / T

We replace

2π / T = √ g / L

T = 2π √L / g

We will use the value of g = 9.8 m / s², the initial length of the pendulum, in general it is 1 m (L = 1m)

With this length the average time period is

T = 2π √1 / 9.8

T = 2.0 s

They indicate that the error accumulated in a day is 15 s, let's use a rule of proportions to find the error is a swing

t = 1 day (24h / 1day) (3600s / 1h) = 86400 s

e= Δt = 15 (2/86400) = 3.5 104 s

The time the clock measures is

T ’= To - e

T’= 2.0 -0.00035

T’= 1.99965 s

Let's look for the length of the pendulum to challenge time (t ’)

L’= T’² g / 4π²

L’= 1.99965 2 9.8 / 4π²

L ’= 0.9926 m

Therefore the amount that should adjust the length is

ΔL = L - L’

ΔL = 1.00 - 0.9926

ΔL = 0.0074 m

You might be interested in

Bats use a process called echolocation to find their food. This involves giving out sound waves that hit possible prey or food.

cupoosta [38]

The type of waves used by bats are sound waves. Most of the species use their larynx to produce ultrasound waves in the frequency range of 20 to 200 kilohertz.
These sound waves are echoed, reflected, by surroundings, in this case food or prey. These reflections are received by the specialized receptor cells in the ears of bats. The reflections are analyzed by the brain to make an image.
Fun fact: The brain cells of bats are also specialized to better analyze the frequency of ultrasound used by the bat.

8 0

3 years ago

Read 2 more answers

A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr

valina [46]

The spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
$T=2 t = 2 \cdot 0.100 s = 0.200 s$
Which means that the frequency is
$f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz$
and the angular frequency is
$\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s$

In a spring-mass system, the maximum velocity of the object is given by
$v_{max} = A \omega$
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
$v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s$

6 0

3 years ago

The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound? Hz.

Pie

The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.

<h2>Period:</h2>

It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

$f = \dfrac 1T$

Where,

$f$ - frequency

$T$ - period = 0.002 s

Put the value in the equation,

$f = \dfrac 1{0.002}\\\\f = 500\rm \ Hz$

Therefore, the frequency of the given sound is 500 Hz.

Learn more about Period:

brainly.com/question/842349

5 0

2 years ago

The Doppler shift can be observed when ____________. Check all that apply. Group of answer choices the source of sound moves tow

castortr0y [4]

Answer:

the source of sound moves towards an observe

Explanation:

The Doppler effect is related to waves such as sound or light. the effect causes an increase or decrease in the frequency of sound light or other waves when the souces either move towards or away from the observer. For example the siren of the train to a person on the platform, the redshift seen by astronomers.

Therefore, The Doppler shift can be observed when the source of sound moves towards an observer From a place closer to the observer than the last wave's crest, each consecutive wave crest is sent. Each wave therefore, takes a little less time than the preceding wave to reach the observer.

6 0

3 years ago

What is an example of a invertebrate that doesn’t have an exoskeleton?

Tatiana [17]

Invertebrate means those organism which doesnot have backbone in their body .Some of the examples are:

1.Spider

2.earthworm

3.Starfish

4.Sea urchins.

hope this will help u a lot....

5 0

3 years ago

Read 2 more answers