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tankabanditka [31]
3 years ago
9

box%20%5Cblue%20%7B%CE%B5%7D%5Chuge%20%5Cfbox%20%5Cred%20%7Bs%7D%5Chuge%20%5Cfbox%20%5Cpurple%20%7B%CF%84%7D%5Chuge%20%5Cfbox%20%5Corange%20%7Bi%7D%5Chuge%20%5Cfbox%20%5Cpink%20%7B%CF%83%7D%5Chuge%20%5Cfbox%20%5Cpink%7B%CE%B7%7D%20" id="TexFormula1" title="\huge \fbox \pink {q}\huge \fbox \green {υ}\huge \fbox \blue {ε}\huge \fbox \red {s}\huge \fbox \purple {τ}\huge \fbox \orange {i}\huge \fbox \pink {σ}\huge \fbox \pink{η} " alt="\huge \fbox \pink {q}\huge \fbox \green {υ}\huge \fbox \blue {ε}\huge \fbox \red {s}\huge \fbox \purple {τ}\huge \fbox \orange {i}\huge \fbox \pink {σ}\huge \fbox \pink{η} " align="absmiddle" class="latex-formula">
1). What is refractive index?​
Physics
2 answers:
Fed [463]3 years ago
6 0

\\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \tt \red{lel \: nvm}

natta225 [31]3 years ago
5 0

Answer:

the refractive index variable is n or n'

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An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?
Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle  = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle  = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical  energy.

The formula of kinetic energy is given as;

              Kinetic energy  = \frac{1}{2} m v²

where m is the mass, V is the velocity

   substitute the parameters in the equation;

                       600  = \frac{1}{2} x m x 15²

                     225m  = 1200

                            m  = \frac{1200}{225}    = 5.33kg

3 0
2 years ago
What characteristic of solitaire did Mendeleev<br> use as a model for his periodic table?
forsale [732]
That the player must produce an arrangement in which each suit is ordered from ace to king
7 0
3 years ago
The maximum speed with which you can throw a stone is about 20 m/s. Can you hit a window 45 m away horizontally and 10 m up from
Allushta [10]

Answer:

 y = 17 m

Explanation:

For this projectile launch exercise, let's write the equation of position

          x = v₀ₓ t

          y = v_{oy} t - ½ g t²

let's substitute

          45 = v₀ cos θ t

          10 = v₀ sin θ t - ½ 9.8 t²

the maximum height the ball can reach where the vertical velocity is zero

 

           v_{y} = v_{oy} - gt

           0 = v₀ sin θ - gt

           0 = v₀ sin θ - 9.8 t

Let's write our system of equations

         45 = v₀ cos θ  t

         10 = v₀ sin θ t - ½ 9.8 t²

         0 = v₀ sin θ - 9.8 t

We have a system of three equations with three unknowns for which it can be solved.

Let's use the last two

        v₀ sin θ = 9.8 t

we substitute

        10 = (9.8 t) t - ½ 9.8 t2

        10 = ½ 9.8 t2

        10 = 4.9 t2

        t = √ (10 / 4.9)

        t = 1,429 s

Now let's use the first equation and the last one

         45 = v₀ cos θ t

         0  = v₀ sin θ - 9.8 t

         9.8 t = v₀  sin θ

         45 / t = v₀ cos θ

we divide

         9.8t / (45 / t) = tan θ

          tan θ = 9.8 t² / 45

          θ = tan⁻¹ ( 9.8 t² / 45 )

          θ = tan⁻¹ (0.4447)

          θ = 24º

Now we can calculate the maximum height

         v_y² = v_{oy}^2 - 2 g y

         vy = 0

          y = v_{oy}^2 / 2g

          y = (20 sin 24)²/2 9.8

          y = 3,376 m

the other angle that gives the same result is

       θ‘= 90 - θ

       θ' = 90 -24

       θ'= 66'

for this angle the maximum height is

 

          y = v_{oy}^2 / 2g

          y = (20 sin 66)²/2 9.8

           y = 17 m

thisis the correct

6 0
3 years ago
A 1kw electric heater is switched on for ten minutes. how much heat does it produce​
Ainat [17]

H= P × t

1kW= 1000w

10 min = 600s

H= 1000×600=600,000J

=> 143.40kcal

4 0
3 years ago
Ohm’s law describes the relationship between which quantities?
VladimirAG [237]
I think its between b or c
5 0
3 years ago
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