<img src="https://tex.z-dn.net/?f=%5Chuge%20%5Cfbox%20%5Cpink%20%7Bq%7D%5Chuge%20%5Cfbox%20%5Cgreen%20%7B%CF%85%7D%5Chuge%20%5Cf

All categories

3 years ago

box%20%5Cblue%20%7B%CE%B5%7D%5Chuge%20%5Cfbox%20%5Cred%20%7Bs%7D%5Chuge%20%5Cfbox%20%5Cpurple%20%7B%CF%84%7D%5Chuge%20%5Cfbox%20%5Corange%20%7Bi%7D%5Chuge%20%5Cfbox%20%5Cpink%20%7B%CF%83%7D%5Chuge%20%5Cfbox%20%5Cpink%7B%CE%B7%7D%20" id="TexFormula1" title="\huge \fbox \pink {q}\huge \fbox \green {υ}\huge \fbox \blue {ε}\huge \fbox \red {s}\huge \fbox \purple {τ}\huge \fbox \orange {i}\huge \fbox \pink {σ}\huge \fbox \pink{η} " alt="\huge \fbox \pink {q}\huge \fbox \green {υ}\huge \fbox \blue {ε}\huge \fbox \red {s}\huge \fbox \purple {τ}\huge \fbox \orange {i}\huge \fbox \pink {σ}\huge \fbox \pink{η} " align="absmiddle" class="latex-formula">
1). What is refractive index?

Physics

2 answers:

Fed [463]3 years ago

6 0

$\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \tt \red{lel \: nvm}$

natta225 [31]3 years ago

5 0

Answer:

the refractive index variable is n or n'

You might be interested in

in a lab, resonance tubes are used to determine experimentally the speed of sound. using the data given, evaluate the best appro

jek_recluse [69]

The approximate speed of sound is about 761 mph or 335.28 meters/second.

<h3>What's the approximate speed of sound?</h3>

If we consider the normal atmosphere at sea level, the speed of sound is about 761 mph or 335.28 meters/second. The speed of sound is different in different mediums such as solid and liquid.

So we can conclude that the approximate speed of sound is about 761 mph or 335.28 meters/second.

Learn more about speed here: brainly.com/question/4931057

#SPJ1

3 0

2 years ago

Mountains forming today due to movement of the plates and mountains forming in the past due to movements of the plates would be

nataly862011 [7]

Answer: d.

Explanation:

3 0

3 years ago

Read 2 more answers

Consider your moment of inertia about a vertical axis through the center of your body, both when you are standing straight up wi

jeka94

Answer:

I₁ / I₂ = 1.43

Explanation:

To find the relationship of the two inertial memits, let's calculate each one, let's start at the moment of inertia with the arms extended

Before starting let's reduce all units to the SI system

d₁ = 42 in (2.54 10⁻² m / 1 in) = 106.68 10⁻² m

d₂ = 38 in = 96.52 10⁻² m

The moment of inertia is a scalar quantity for which it can be added, the moment of total inertia would be the moment of inertia of the man (cylinder) plus the moment of inertia of each arm

I₁ = I_man + 2 I_ arm

Man indicates that we can approximate them to a cylinder where the average diameter is

d = (d₁ + d₂) / 2

d = (106.68 + 96.52) 10-2 = 101.6 10⁻² m

The average radius is

r = d / 2 = 50.8 10⁻² m = 0.508 m

The mass of the trunk is the mass of man minus the masses of each arm.

M = M_man - 0.2 M_man = 80 (1-0.2)

M = 64 kg

The moments of inertia are:

A cylinder with respect to a vertical axis: Ic = ½ M r²

A rod that rotates at the end: I_arm = 1/3 m L²

Let us note that the arm rotates with respect to man, but this is at a distance from the axis of rotation of the body, so we must use the parallel axes theorem for the moment of inertia of the arm with respect to e = of the body axis.

I1 = I_arm + m D²

Where D is the distance from the axis of rotation of the arm to the axis of the body

D = d / 2 = 101.6 10⁻² /2 = 0.508 m

Let's replace

I₁ = ½ M r² + 2 [(1/3 m L²) + m D²]

Let's calculate

I₁ = ½ 64 (0.508)² + 2 [1/3 8 1² + 8 0.508²]

I₁ = 8.258 + 5.33 + 4.129

I₁ = 17,717 Kg m² / s²

Now let's calculate the moment of inertia with our arms at our sides, in this case the distance L = 0,

I₂ = ½ M r² + 2 m D²

I₂ = ½ 64 0.508² + 2 8 0.508²

I₂ = 8,258 + 4,129

I₂ = 12,387 kg m² / s²

The relationship between these two magnitudes is

I₁ / I₂ = 17,717 /12,387

I₁ / I₂ = 1.43

3 0

3 years ago

Reactants → products

Nat2105 [25]

The answer is A

Explanation: the conservation of matter means that the mass stays the same

4 0

3 years ago

Read 2 more answers

A solenoid having an inductance of 6.95 μh is connected in series with a 1.24 kω resistor. (a) if a 12.0 v battery is connected

Serggg [28]

In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is

Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms

The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
$I= \frac{V( 1- e^{-t/τ} )}{R}$ , where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
$7.12x 10^{-3} = \frac{12( 1- e^{-t/5.6x 10^{-9} } )}{1240}$

t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
$I= \frac{12( 1- e^{-1 } )}{1240}$

I = 6.12 mA

3 0

4 years ago