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3 years ago

I don't understand it asking me what the earth look like when the moon is a new moon

Physics

2 answers:

Aloiza [94]3 years ago

8 0

Answer:it will look the same

Explanation:

the earht will aways be the same

wariber [46]3 years ago

6 0

Explanation:

From a new Moon, when the Moon is situated in orbit between the Earth and the Sun with its dark side in shadow facing towards us, the amount of lunar surface visible from the Earth increases through waxing crescent, first quarter and waxing gibbous phases until it becomes full.

The new moon is the phase that is invisible to us here on Earth because the moon is between the earth and the sun, and its illuminated side is facing away from us. A solar eclipse occurs when the moon moves in front of the sun, blocking it from our view on Earth.

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A train moves at constant velocity of 90km/h. How far will it go in 0.25h.

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In a quarter of an hour it will travel 1/4 x 90 = 22.5Km

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3 years ago

Which of the following is NOT a natural source of light?

mixas84 [53]

Answer:

neon light

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2 years ago

Read 2 more answers

2. Ms. Evelyn lined up her students at recess on the soccer field. She told each student to kick a soccer ball as hard as they c

mash [69]

Answer

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2 years ago

Four charges of magnitude +q are placed at the corners of a square whose sides have a length d. What is the magnitude of the tot

guapka [62]

Answer:

$F = \frac{4kqQb}{(b^2 + \frac{d^2}{2})^{1.5}}$

Explanation:

Since all the four charges are equidistant from the position of Q

so here we can assume this charge distribution to be uniform same as that of a ring

so here electric field due to ring on its axis is given as

$E = \frac{k(4q)x}{(x^2 + R^2)^{1.5}}$

here we have

x = b

and the radius of equivalent ring is given as the distance of each corner to the center of square

$R = \frac{d}{\sqrt2}$

now we have

$E = \frac{4kq b}{(b^2 + \frac{d^2}{2})^{1.5}}$

so the force on the charge is given as

$F = QE$

$F = \frac{4kqQb}{(b^2 + \frac{d^2}{2})^{1.5}}$

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3 years ago

An astronaut orbits planet Y in her spaceship. To remain in orbit at 410km above the planet's center, she maintains a speed of 6

choli [55]

Formula for orbital speed, v = √(GM/R)

Where G is the universal gravitational constant, M = Central Mass,

R = Distance between centers of Mass.

Given. v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²

68 = √(GM/R)

68 = √(6.674 * 10⁻¹¹ * M/410000)

68² = (6.674 * 10⁻¹¹ * M)/410000

(68² * 410000) / 6.674 * 10⁻¹¹ = M

2.84 × 10¹⁹ = M

Mass of Planet Y = 2.84 × 10¹⁹ kg

3 0

3 years ago

I don't understand it asking me what the earth look like when the moon is a new moon​

I don't understand it asking me what the earth look like when the moon is a new moon