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Andre45 [30]
3 years ago
9

Pls help.. .....................................................................................................................

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

It is the last one 43,756

Step-by-step explanation:

I dont exactly know the explanation, I did it in my head and checked it on a calc

sashaice [31]3 years ago
3 0

Answer:

your answer is 43,756

Step-by-step explanation:

you just move the decimal 4 times to the right

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K = mv / 2 solve for m . HELP PLEASE HURRY!
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Answer:

  m = 2k/v

Step-by-step explanation:

Identify the coefficient of m (v/2) and multiply by its inverse (2/v).

  (2/v)k = (2/v)m(v/2) . . . . multiply both sides of the equation by 2/v

  2k/v = m . . . simplify

  m = 2k/v

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2 years ago
Find the value of x.<br> M M<br> (2x<br> 10)<br> (2x + 40)<br> N<br> X=
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Could you state the question in the correct order?? Like is N supposed to be there?

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2 years ago
Cos(2x) - 3cos(x) + 2= 0 ??
alexandr1967 [171]
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3 years ago
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Likurg_2 [28]

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3 years ago
Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
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