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Andre45 [30]
3 years ago
9

Pls help.. .....................................................................................................................

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

It is the last one 43,756

Step-by-step explanation:

I dont exactly know the explanation, I did it in my head and checked it on a calc

sashaice [31]3 years ago
3 0

Answer:

your answer is 43,756

Step-by-step explanation:

you just move the decimal 4 times to the right

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Simplify each expression, #1: 4(f+2g) - 4g +f. #2: 5g(9m-2) + 3g
Serjik [45]

Answer:

1) 5f

2) 45gm-7g

Step-by-step explanation:

hope this helped!

7 0
2 years ago
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
3 years ago
What do 89/90 equal but not as a decimal or a percent as a fraction HELP ME
sergeinik [125]

Answer:

it equals 89/90

Step-by-step explanation:

the gcf of 89, 90 is 1, so the fraction can not be simplified. The answer is 89/90.

3 0
3 years ago
Question 17 of 33
butalik [34]

Answer:

C

Step-by-step explanation:

i took the test

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3 years ago
The coordinates of the midpoint of
Alecsey [184]

Answer: yo mommy a clown

Step-by-step explanation:

7 0
3 years ago
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