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3 years ago

What is the slope of the line that passes through the points (-10, 0) and (-13, 3)? Write your answer in simplest form.

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:The slope of the line that passes through (-10, 0) and (-13, 3) is "-1".

Given points are:

As we know, the formula,

→

By substituting the above points, we get

→

Thus the solution is right.

Step-by-step explanation:

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Is circle Tangent lines

Sergio [31]

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4 years ago

1) Factor the polynomial using the GCE.<br> 2x2 + 6x

yarga [219]

Answer:

$2x(x+3)$

Step-by-step explanation:

$2x^{2} +6x$

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4 years ago

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Write the expression in factored form. 81m^4 -25

Makovka662 [10]

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3 years ago

PLEASE HELP IK ITS SO HARD TO UNDERSTAND FOR MEEE

Minchanka [31]

Answer: 15

Step-by-step explanation:

First step is to find the slope of the line given

y = -x - 2

y = mx + c where m is the slope of the line so the slope of the line is -1

If 2 lines are perpendicular to one another, the product of the slopes is -1 so the slope of the perpendicular line is -1/-1 = 1

y = 1x + c or y = x + c

As the line passes through the coordinate (-5,10), we can substitute the x and y value of the coordinates into the equation

10 = -5 + c

c = 15

So the equation of the line is y = x + 15

4 0

2 years ago

Can someone answer this soon?!?

Sever21 [200]

First get all the terms on the same side:

$x^2 + 7x - 4 = 0$

Now solve using the quadratic formula which is:

$\frac{-b±\sqrt{b^2 - 4ac} }{2a}$

Plug in the values:

$\frac{-7± \sqrt{49-4(1)(-4)} }{2}$

So the answer is:

$\frac{-7 ± \sqrt{65} }{2}$

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3 years ago