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Charra [1.4K]
4 years ago
15

Use the graph of f to estimate the local maximum and local minimum. (5 points)

Mathematics
2 answers:
vovikov84 [41]4 years ago
4 0

Answer:

Local maximum: (0,1)  

Local minimum: (-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)

Step-by-step explanation:

To estimate the local maximum and local minimum using graph.

Local maximum: It is largest value of function for all other values of function near by.

Local minimum: It is smallest value of function for all other values of function near by.

A function has two extrema maxima or minima.

Please see the attachment for graph.

In graph highest point only 1, Only one local maximum at x=0

Local maximum: (0,1)

In graph two lowest point at x=-\pi\text{ and }x=\dfrac{3\pi}{2}

Local minimum: (-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)

Hence, Local maximum: (0,1) ; Local minimum: (-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)

Alex4 years ago
3 0
The one under the one you picked but im not 100% sure
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Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

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