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3 years ago

Use the graph of f to estimate the local maximum and local minimum. (5 points)

Mathematics

2 answers:

vovikov84 [41]3 years ago

4 0

Answer:

Local maximum: (0,1)

Local minimum: $(-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)$

Step-by-step explanation:

To estimate the local maximum and local minimum using graph.

Local maximum: It is largest value of function for all other values of function near by.

Local minimum: It is smallest value of function for all other values of function near by.

A function has two extrema maxima or minima.

Please see the attachment for graph.

In graph highest point only 1, Only one local maximum at x=0

Local maximum: (0,1)

In graph two lowest point at $x=-\pi\text{ and }x=\dfrac{3\pi}{2}$

Local minimum: $(-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)$

Hence, Local maximum: (0,1) ; Local minimum: $(-\pi,-1)\text{ and }(\dfrac{3\pi}{2},-1)$

Alex3 years ago

3 0

The one under the one you picked but im not 100% sure

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2 years ago

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kramer

Answer:

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3 years ago

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Answer the following questions:

timama [110]

Answer:

Question 1: 76 dollars. ($76)

2. 1/5

3. 1/19

4. 1/5

Step-by-step explanation:

QUESTION 1:

228 (the amount Mrs. Nicci had) divided by 3 (children) is equal to 76

228/3 = 76

QUESTIONS 2, 3, AND 4.

2. Find the greatest common divisor (GCD). the GCD of 14 and 70 is 14. Then, divide the numerator and denominator by 14.

14/14 = 1

70/14 = 5

WHICH EQUALS 1/5!!

3. Find the greatest common divisor (GCD). the GCD of 5 and 95 is 5. Divide both the numerator and denominator by 5.

5/5= 1

95/5= 19

WHICH EQUALS 1/19!!

4. Find the greatest common divisor (GCD). the GCD of 12 and 60 is 12. So (like we have been doing for the whole part of this question), divide both the numerator and denominator by 12, which is the GCD.

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2 years ago

Find the equation of a parabola with a focus at (0,-1) and a directrix at y = 4.

Anastasy [175]

Answer:

y = -1/10x^2 +2.5

Step-by-step explanation:

The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:

-1 -4 = -5

So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).

The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...

y = (1/(4p))(x -h) +k

y = -1/10x^2 +2.5

_____

You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.