Answer:
It looks as though it would be A because it starts at 30 and goes up steadily by 5. B increases too quickly, C does not increase, and D decreases.
Step-by-step explanation:
Well, let's first write these as points.
( 2 , 50 )
( 4 , 100 )
We can see that when "x" is reduced by 2, "y" is reduced by 50. This means that if we reduce "x" by 1, "y" will be reduced by 25. Thus, we can say that if "x" is 1, "y" will be 25.
( 1 , 25 )
What we know that 25 * 1 = 25, and that 2 * 25 = 50. We can see that multiplying "x" by 25 will give us our "y". We can now write this as an equation.
y = 25x
Answer:
35
Step-by-step explanation:
if you order the numbers from least to greatest, there are 14 numbers (which is even which means their is going to be two median. when you have two medians you add them and then divide them by 2) 35 + 35 = 70, 70 divided by 2 is 35. the answer is 35!
The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.
<h3>How to Find the Graph of a Linear Inequality?</h3>
The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.
On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.
Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.
Graph A has a slope of -1/3 and the shaded part is above the boundary line.
Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.
Learn more about inequality graph on:
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We can find the acceleration via
We have
Then by definition of average acceleration,
so that
We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is
Then
