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3 years ago

How to multiply 18 3/8 x 1/4

1 answer:

4 0

Decimal Form:
4.59375

Exact Form:
147/32

Mixed Number Form: 4 19/32

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50 Points and brainliest, simple data

Masja [62]

14 | 7 | 21
6 | 3 | 9
20 |10| 30

i hope you understand how im trying to put i

7 0

2 years ago

A little boy goes shopping and purchases 12 tomatoes. On the way home, all but 9 get mushed and ruined. How many tomatoes are le

Nezavi [6.7K]

Answer:

Step-by-step explanation:

its so easy all you have to do is 12-9=3

6 0

3 years ago

Read 2 more answers

Given the piece wise function show below, select all that are true

NeTakaya

Answer:

Option (C) and (D)

Step-by-step explanation:

Given piecewise function is,

f(x) = 2x, x < 1

5, x = 1

$x^{2}$ , x > 1

Option (A),

x = 5 means x > 1

So the function will be,

f(x) = $x^{2}$

f(5) = (5)²

= 25

Therefore, f(5) = 1 is not correct.

Option (B),

x = -2 means x < 1

f(x) = 2x will be applicable.

f(-2) = 2(-2) = -4

Therefore, f(-2) = 4 is not correct.

Option (C)

For x = 1,

f(1) = 5

Therefore, f(1) = 5 is the correct option.

Option (D)

x = 2 means x > 1 and the function defined will be,

f(x) = x²

f(2) = 2²

= 4

Therefore, f(2) = 4 will be the correct option.

Options (C) and (D) will be the answer.

7 0

3 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

3 years ago

Which table does NOT represent a linear function?

chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

x values: -1, 0, 1, 2

- we add 1 each time

y values: 8, 5, 2, -1

- we subtract 3 each time

$\rule{200}{2}$

Let's try the next one:

x values: -1, 0, 1, 2

- we add 1 each time

y values: 5, 10, 15, 20

- we add 5 each time

$\rule{200}{2}$

Let's try the third one:

x values: -1, 0, 1, 2
- we add 1 each time

y values: 15, 18, 20, 21

- we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

x values: -1, 0, 1, 2

- we add 1 each time

y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0

2 years ago