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andrey2020 [161]
3 years ago
12

on the coordinate grid, the graph of y=³√-x-1 is shown. it is a reflection and translation of y= ³√x. what is the range of the g

raphed function? a). {x |-2 < x < 2} b). {y |-2 < y < 2} c). {x | x is a real number} d). {y | y is a real number}
Mathematics
2 answers:
Leni [432]3 years ago
6 0
The range is the set of possible images, i.e. "y".

So you can discard options "a" and "c".

2 is a possible image, and all the real numbes are.

Then the answer is "d. y | y is a real number"
professor190 [17]3 years ago
3 0

Answer:D on e2020 100%

Step-by-step explanation:

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Victoria is counting all of quarters and dimes from the family piggy bank for the month. If there are 12 times as many dimes are
saw5 [17]

Let number of quarters in family piggy bank = x

Let number of dimes in family piggy bank = y


Given that "there are 12 times as many dimes are there are quarters". so we can write equation:

y=12x...(i)


Given that " total change is worth $21.75".

We know that 1 quarter = $0.25 and 1 dime = $0.10

So other equation will be :

0.25x+0.10y=21.75...(ii)

Now we just need to solve both equations.

Plug (i) into (ii)


0.25x+0.10y=21.75

0.25x+0.10(12x)=21.75

0.25x+1.2x=21.75

1.45x=21.75

x=15


plug x=15 into (i)

y=12x=12*15=180


Hence final answer is given as:

Number of quarters in family piggy bank = 15

Number of dimes in family piggy bank = 180



4 0
2 years ago
) Write 3 - as an improper fraction.<br> Write 3 7/10 as an improper question
schepotkina [342]
3 as an improper fraction is 3/1

3 7/10 as an improper fraction is 37/10

hope this helps! :))
3 0
3 years ago
The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

6 0
3 years ago
Jonathan records how 90 pupils travelled to school on one day and represents this information on the pie chart below.
xeze [42]

Answer:

86.4

Step-by-step explanation:

First adding up all the percentages on the chart you get 360

Then figuring out what 24° of 360 is

You then get 86.4

4 0
2 years ago
The number of customers in a store on the first day is represented by: (6x - 3) The number of customers on the second day is rep
Scorpion4ik [409]

Answer:the expression is 5x - 2

Step-by-step explanation:

The number of customers in a store on the first day is represented by: (6x - 3).

The number of customers on the second day is represented by: (x - 1)

An expression to find how many more customers visited the store on the first day would be the difference between the number of customers that visited the store on the first day and the number of customers that visited the store on the second day. The expression becomes

6x - 3 - (x - 1)

= 6x - 3 - x + 1

= 6x - x - 3 + 1

= 5x - 2

7 0
3 years ago
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