Answer:
Quantity A because it changes with gravitational pull.
Explanation:
Mass defines the constitutive matter of an object. It is immutable (does not change). Although it could be converted into energy, the matter is constant.
On the other hand, the weight of an object (gravitational force) depends on the acceleration due to gravity.
That is why an astronaut weighs about three times more on earth than on Mars. The gravitational acceleration on Mars is about one third that on earth.
Answer:
Height = 8 cm
You will need this formula (see attached):
Volume = [PI * 8 * (2² + 2*4 + 4²)] / 3
Volume = [3.14159265 * 8 * (4 + 8 + 16)] / 3
Volume = 234.57 cubic centimeters
Source: http://www.1728.org/volcone.htm
Step-by-step explanation:
The answer is <span>5, 4, 2
</span>
Among all choices we have 5, so
x = 5
x - 5 = 0
Let's divide the expression by (x - 5) using the long division:
x³ - 11x² + 38x - 40
(x - 5) * x² = x³ - 5x² Subtract
____________________________
-6x² + 38x - 40
(x - 5) * (-6x) = -6x² + 30x Subtract
____________________________
8x - 40
(x - 5) * 8 = 8x - 40 Sutract
____________________________
0
Thus: x³ - 11x² + 38x - 40 = (x - 5)(x² - 6x + 8)
Now, let's simplify x² - 6x + 8.
x² - 6x + 8 = x² - 2x - 4x + 8 =
= x² - 2*x - (4*x - 4*2) =
= x(x - 2) - 4(x - 2) =
= (x - 4)(x - 2)
Hence:
x³ - 11x² + 38x - 40 = (x - 5)(x - 4)(x - 2)
To calculate zero:
x³ - 11x² + 38x - 40 = 0
(x - 5)(x - 4)(x - 2) = 0
x - 5 = 0 or x - 4 = 0 or x - 2 = 0
x = 5 or x = 4 or x = 2
Since a side is only 6 inches long and the total perimeter is 36; take 36/6 and you get 6. The only figure with six sides is a hexagon, thus your answer is hexagon.
Answer:
Is 6x and 4x+2 equivalent
? No!
Step-by-step explanation:
6x doesn't equal 4x+2
In order for them to be the same you would have to add the same terms example:
4x+2x would equal 6x
Extra explaining:
The only way for those term to be added would be if they had the same variable since only 4x has a variable the 2 cant be added. In math you CANNOT move your variables off of a number and add them back on after.
