7x20=140. 7x2000=14000. The only thing that changes the product of these numbers is the amount of zeros behind the 2. Since the only two numbers that affect the answer is the 7 and the 2. (7x2=14). The number of zeros behind the 2 affect how many zeros will be included in the product.
The answer is B.
Function means every x corresponds to one unique y value. ACD all have duplicates correspondence.
715 because 275/5= 55 then 55x13 will give you 715
Answer:
48+23(6)½
Step-by-step explanation:
A = l × w
A =[(8-(6)^½) × (9+4(6)^½)]
A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]
A =(72 + 32(6)^½ - 9(6)^½ - 24)
A =(72 - 24 + 32(6)^½ - 9(6)^½)
A =(48 + 23(6)^½)
Answer: P = 0.75
Step-by-step explanation:
Hi!
The sample space of this problems is the set of all the possible sales. It is divided in the disjoint sets:

We have also the set of sales of boat accesories
, the colored one in the image.
We are given the data:

From these relations you can compute the probabilities of the intersections colored in the image:

You are asked about the conditional probability:

To calculate this, you need
. In the image you can see that the set
is the union of the two disjoint pink and blue sets. Then:

Finally:
