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3 years ago

7

Divide. (35x^2 – 11x -8) divided by(5x+2)

1 answer:

Thepotemich [5.8K]3 years ago

5 0

Attached you will see the answer (use polynomial division)

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Math help,, please !! asap <br> 10 points rewarding :)) thanks u

VladimirAG [237]

1. A in some part is correct, but the triangles are indeed correct, and the argument is for HL, so the answer is C

2. Are congruent by SSS (both shares a side).

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Evaluate. Write your answer as a fraction or whole number without exponents.

Aleks [24]

The answer to the question is 1/27

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Find the radius r of C.

garik1379 [7]

Answer:

$r=10.5$

Step-by-step explanation:

$(r+7)^2=r^2+14^2$

$r^2+14r^2+49=r^2+196$

$14r=196-49$

$14r=147$

$r=147/14$

$r=10.5$

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hope it helps..

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3 years ago

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The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the

valentinak56 [21]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : $\frac{a}{b}$

Suppose the second fraction is : $\frac{c}{d}$

The sum of both fraction is given as : $\frac{5}{6}$

$\frac{a}{b}+\frac{c}{d}=\frac{5}{6}$ .......................equation (1)

The difference of both fraction is given as : $\frac{1}{2}$

$\frac{a}{b}-\frac{c}{d}=\frac{1}{2}$ .........................equation (2)

Adding equation (1) and equation (2)

$\frac{c}{d} \ will \ be \ cancelled$

$\frac{2a}{b}=\frac{5}{6}+\frac{1}{2}$

making common denominator

$\frac{2a}{b}=\frac{5}{6}+ \frac{3}{6}$

$\frac{2a}{b}=\frac{8}{6}$

Hence,

$\frac{a}{b}=\frac{2}{3}$

Plugging the value of $\frac{a}{b}$ in equation (1)

$\frac{2}{3}+\frac{c}{d}=\frac{5}{6}$

Subtracting $\frac{2}{3}$ in both sides

$\frac{c}{d}=\frac{5}{6}-\frac{2}{3}$

$\frac{c}{d}=\frac{1}{6}$

Hence both fractions are $\frac{2}{3} \ and \ \frac{1}{6}$ ...................Answer

Hope it will help :)

7 0

3 years ago

Show that the roots of the equations

harkovskaia [24]

Answer:

The roots are real and distinct.

Step-by-step explanation:

Given the following equation:

$x^{2} + kx - k -2 =0$

In this problem, a = 1, b = k and c = -k - 2

The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.

We get,

(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)

= k² + 4k + 8

Let's check:

At k = -2,

$(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4


$

At k = 0,

$(0)^2 + 4(0) + 8 = 8$

At k = -100,

$(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608$

Therefore, we can conclude that for all values of k, the roots are real and distinct.

This has been a long way in answering this question, so it would be great if you could mark me as brainliest

3 0

3 years ago