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dezoksy [38]
3 years ago
12

How many £7.50 is there in £217.5?​

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

29

Step-by-step explanation:

217.5÷7.50=29

............ur welcome...............

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Travis has a customer who wants to purchase a portable CD player for $45 at a 20% discount. What is the amount of the discount?
kherson [118]
Just do 45x0.2 then take that number off of $45 thats your answer
8 0
3 years ago
Read 2 more answers
Write 54 + 63 as the product of the GCF of 54 and 63 and another sum
levacccp [35]

Answer:

9*(6+7)

Step-by-step explanation:

First, we have to find the Greatest Common Factor (GCF), to do this we have to see all the factors of 54 and 63 and find the greatest factor that they have in common.

Factors of 54

1,2,3,6,9,18,27,54

Factors of 63

1,3,7,9,21,63

The GCF is 9 because is the greatest factor that is common to both numbers.

Now we have to divide 54/9 and 63/9

54/9 = 6

63/9 = 7

So now we can write the product of the GCF and another sum:

9*(6+7)

<em>We can prove this by solving both expressions:</em>

<em>54+63 = 9*(6+7)</em>

<em>117 = 9*13</em>

<em>117 = 117 </em>

<em>The results are equal so we prove it is right.</em>

8 0
3 years ago
Read 2 more answers
HEEEEEEEEEEELLLLLLLLPPPPPPPPPPP. PPPPPPLLLLLLEEEEEEAAAAASSSSSEE When Laura started her career at the age of 24, she deposited $8
Irina18 [472]

Answer:

she mad 52,000

Step-by-step explanation:

she made 52,000 by working by her job

6 0
3 years ago
Solve for A<br> Exact (no rounding, no calculator needed)<br><br> 0 = A^2 + 13A + 36
marysya [2.9K]

Answer:

-4 or -9

Step-by-step explanation:

-a^2-13a-36=0

(-a-4)(a+9)=0

-a-4=0

a+9=0

a= -4, -9

3 0
3 years ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
aksik [14]

Answer:

the expected value of this raffle if you buy 1​ ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at​ $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as​ follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Thus; the amount and the corresponding probability can be computed as:

Amount                            Probability

$500 -$1 = $499                1/5000

$300 -$1 = $299                3/5000

$50 - $1 = $49                     5/5000

$5 - $1 = $4                      20/5000

-$1                                   1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is  as follows:

E(x) = \sum x  * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000}  + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016  + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

Thus; the expected value of this raffle if you buy 1​ ticket = -0.65

7 0
3 years ago
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