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Jobisdone [24]
2 years ago
8

Identify the substance given to the technician.

Chemistry
1 answer:
katrin [286]2 years ago
5 0
The substance would be sodium nitrate, to figure this out all you need to do is read each sentence carefully and see if whatever the lab technician notices happening to the substance does it match with any of the substances listed in the table, if it does not match, any one description we can eliminate that compound as a choice. Carry this method of elimination basically until you come to the last sentence. Since the substance melts at temperature above the melting point, it can't be potassium chromate as it would change state at a temperature of 974 degrees Celsius, not high of temperature for the change, as the oven is at 450 degrees Celsius only.
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. Using the pH scale below what would be the pH value of an Acid? *
earnstyle [38]

Answer : The pH value of an acid is below 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

pH=-\log [H^+]

When the pH less than 7 then the solution is acidic and the concentration of hydrogen ion is greater than hydroxide ion.

When the pH more than 7 then the solution is basic and the concentration of hydrogen ion is less than hydroxide ion.

When the pH is equal to 7 then the solution is neutral and the concentration of hydrogen ion is equal to the hydroxide ion.

Hence, the pH value of an acid is below 7.

6 0
3 years ago
What is one example of boyles law
damaskus [11]
One of the examples of Boyles law in action is a syringe 




3 0
3 years ago
Why is hydrogen placed with the elements in group 1a??
N76 [4]
Because it has atomic no. = 1 (according to modern periidic table)
5 0
3 years ago
What is the pH of a 0.28 M solution of ascorbic acid
Nady [450]

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² /  [0.28 -x ]

x² + 8.0*10⁻⁵x  - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

3 0
3 years ago
PLEASE SHOW YOUR WORK!!
Rom4ik [11]

Answer:

6. 355.1 g of Na₂SO₄ can be formed.

7. 313 g of LiNO₃ were needed

Explanation:

<u>Excersise 6</u>.

The reaction is:  2 NaOH + H₂SO₄ --> 2 H₂O + Na₂SO₄

2 moles of sodium hydroxide react with 1 mol of sulfuric acid to produce 2 moles of water and 1 mol of sodium sulfate.

If we were noticed that the acid is in excess, we assume the NaOH as the limiting reactant. Let's convert the mass to moles (mass / molar mass)

200 g / 40 g/mol = 5 moles.

Now we apply a rule of three with the ratio in the reaction, 2:1

2 moles of NaOH produce 1 mol of sodium sulfate.

5 moles of NaOH would produce (5 .1)/2 = 2.5 moles

Let's convert these moles to mass (mol . molar mass)

2.5 mol . 142.06 g/mol = 355.1 g

<u>Excersise 7.</u>

The reaction is:

Pb(SO₄)₂+ 4 LiNO₃ → Pb(NO₃)₄  +  2Li₂SO₄

As we assume that we have an adequate amount of lead (IV) sulfate, the limiting reactant is the lithium nitrate.

Let's convert the mass to moles (mass / molar mass)

250 g / 109.94 g/mol = 2.27 moles

Let's make a rule of three. Ratio is 2:4.

2 moles of lithium sulfate were produced by 4 moles of lithium nitrate

2.27 moles of Li₂SO₄ would have been produced by ( 2.27 .4) / 2 = 4.54 moles.

Let's convert these moles to mass (mol . molar mass)

4.54 mol . 68.94 g/mol = 313 g

5 0
3 years ago
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