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igomit [66]
3 years ago
12

What makes the smell in chlorine?

Chemistry
1 answer:
padilas [110]3 years ago
7 0

Pool smell is due, not to chlorine, but to chloramines, chemical compounds that build up in pool water when it is improperly treated. Chloramines result from the combination of two ingredients: (a) chlorine disinfectants and (b) perspiration, oils and urine that enter pools on the bodies of swimmers.


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If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of NaCl would be made?
Ket [755]
Number of moles of FeCl2 used = mass/ molar mass 
Number of moles = 507/126.751 = 4.
If one mole of Fe reacts with two moles of sodium 
Then 4 moles of Fe produces 8 moles of sodium.
Number of moles of sodium = mass/molar mass
Molar mass of sodium chloride = 23 +35.5 = 58.5 g/mol
Hence mass = 8 * 58.5 = 468 g. Hence Option A.

6 0
3 years ago
What is the volume, in liters, of 2.00 moles of hydrogen at STP?
Ber [7]
The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.
8 0
3 years ago
The specific heat of zinc is 0.39 J/g*°C. How much energy needed to change the temperature of 34g of zinc from 22°C to 57°C. Is
Svetlanka [38]

Answer:

464.1 J absorbed.

Explanation:

Given data:

Specific heat of zinc =  0.39 J/g°C

Mass of zinc = 34 g

Temperature changes = 22°C to 57°C

Energy absorbed or released = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57°C -  22°C

ΔT = 35°C

Q = m.c. ΔT

Q = 34 g. 0.39 J/g°C. 35°C

Q = 464.1 J

6 0
3 years ago
Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.
Arada [10]

Answer:

X = 7

Explanation:

4 0
2 years ago
A pale of sand and water
zhuklara [117]

Answer:

I have no idea what you mean.

Explanation:

6 0
3 years ago
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