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alexgriva [62]
3 years ago
14

A 56 kg miniature horse weighs 268 fewer kilograms than shetland pony

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0
If the mini horse is 56kg and it's 268kg less than a Shetland pony then a Shetland pony would weigh 56+268=324kg
Studentka2010 [4]3 years ago
6 0
Let
x--------> Shetland pony's <span>weigh
y--------> M</span><span>iniature horse's weigh

we know that
</span>y=56 kg
x=268+y \\ x=268+56 \\ x=324 kg

the answer is
Shetland pony's weigh is 324 kg
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irinina [24]

The probability of drawing a two and another 2 is 1/72

<h3>What is probability?</h3>

Probability is the likelihood or chance that an event will occur

  • Since the total number in the board game is 9, hence the probability of drawing a 2 will be 1/9

  • The probability of drawing the second 2 will be 1/8

  • Pr(drawing a 2, then drawing another 2) = 1/9 * 1/8

Pr(drawing a 2, then drawing another 2) = 1/72

Hence the probability of drawing a two and another 2 is 1/72

learn more on probability here: brainly.com/question/24756209

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In basketball, each shot made is worth 1, 2, or 3 points. Miles scored a total of 27 points in his most recent game. He made thr
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Answer:6

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Subtract the three 1 point shots

Subtract the four 3 point shots

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3 years ago
Square root of y^2 times y^2
Galina-37 [17]
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The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
3 years ago
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