Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
They could go flying out the window, getting seriously injured. This could also leave to death.
Answer:EL SIGLO 20
Explanation:POR EMILIANO ZPAATA
Answer:
Explanation:
The code is not provided in the question but can be easily found online. The code is written in Java and the Rectangle class contains the following variables for the Rectangle object
double x;
double y;
double width;
double height;
The x and y represent the starting positions and then the width and height are added to these starting positions to indicate the endpoints. Ultimately, these four points create the rectangle. The following method detects if these points from the rectangle passed as an argument are within the rectangle in question
public boolean contains (Rectangle r) {
return x < r.x + r.width && x + width > r.x && y < r.y + r.height && y + height > r.y;
}
