How is six and five hundredths written in expanded notation and numerals
1 answer:
Answer:
In Expanded notation it is
In numerals it is 6.05
Step-by-step explanation:
Expanded notation
Expanded notation is a helpful way to rewrite numbers in order to show the place value of each digit.
Normal number of we have
.........,Hundred, Tens ,Unit
eg. 1.) 514
5 = hundred place
1 = tens place
4= unit place
Now for decimal numbers
tenths,hundredths,thousandths........
eg. 1.) 0.25
0 = unit place
2 = tenths place
5 = hundredths place
We will have example in numerals and it expanded notation.
1.
6.05 ( six and five hundredths)
Expanded form
Here,
6 is in Unit place
0 is in Tenths place
5 is in Hundredths place
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Answer:
Option A
Step-by-step explanation:
Answer:
Therefore the solution is = k{-7,5,1} where k ∈R
Step-by-step explanation:
Given that,
f₁(x) =x
f₂(x)= x²
f₃(x)= 7x - 5x²
Also,
g(x) = c₁f₁(x)+c₂f₂(x)+c₃f₃(x)
Putting the values of f₁(x), f₂(x) and f₃(x).
g(x) = c₁.x+c₂x²+c₃(7x-5x²)
Given condition that g(x)= 0
∴ c₁.x+c₂x²+c₃(7x-5x²)=0
⇒(c₁+7c₃)x +(c₂-5c₃)x² = 0
Comparing the coefficients of x and x²
∴c₁+7c₃=0 and c₂-5c₃ =0
Let c₃= k [k∈R]
Then c₁ = -7k and c₂=5k
Therefore the solution is = { c₁,c₂,c₃}
= {-7k, 5k, k}
=k{-7,5,1}