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choli [55]
3 years ago
6

Solve the following system of equations algebraically 3x-y=0 5x+2y=22

Mathematics
1 answer:
Lyrx [107]3 years ago
3 0

3x  -  y  = 0     ⇒   2(3x  -  y  = 0 )   ⇒   6x - 2y = 0

5x + 2y = 22  ⇒   1(5x + 2y = 22)   ⇒   <u>5x + 2y</u> = <u>22 </u>

                                                              11x         = 22

                                                                x          = 2

3x  -  y  = 0   ⇒   3(2) - y = 0   ⇒   6 - y = 0   ⇒   6 = y

Answer: x=2, y=6

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Answer: $270

Step-by-step explanation:

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3 years ago
The equation of line v is y=9x+1. Line w is perpendicular to line v and passes through (3, – 2). What is the equation of line w?
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Step-by-step explanation:

Remember the general form of a linear equartion: y=mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

The equation of line v (y=9x+1) has a slope of 9. A perpendicular line with have a slope equal to the negative inverse of the reference line. So the line we want will have a slope of -(1/9). That gives us y = -(1/9)x + b. Any vale of b will produce a line that is perpendicular. But we want a line that goes through point (3,-2). All we need to do is find a value for b that will make that wish come true.

Use the point (3,-2) in y = -(1/9)x + b and solve for b:

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