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8_murik_8 [283]
3 years ago
5

Answer fast!!!!!!!!!!!

Mathematics
1 answer:
solmaris [256]3 years ago
4 0
B.) is the answer........
.because the object is in axonometry, and the front view will be a square
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Which of the following question is not considered a statistical question?
vekshin1

Answer:

B. How many total customers were at the story today?

Step-by-step explanation:

Option 'B' is not a statistical question because there is not more than one answer.

There is only one answer to this question.

Option 'A,' 'C,' and 'D' are statistical questions because there is more than one answer.

<em>What amounts did each person at the store spend on their purchase?</em>

This question has more than one answer.

<em>How long did each customer spend shopping at the store?</em>

<em>What are the heights of each customer who entered the store?</em>

These questions have more than one answer as well.

Statistical questions are questions that have more than one answer. This means you can collect data.

I, therefore, believe that option 'B' is not a statistical question.

7 0
3 years ago
If you distribute the 3 first in the equation 3(x+2) = 21, what does the second step of your solution process look like?
fenix001 [56]

Answer:

the anser to the entire equation is 5

Step-by-step explanation:

after distributing the three, you have to subtract over the 6 to get 3x=15, then divide by 3 to get five

3 0
3 years ago
Read 2 more answers
Which shows another way to write 4 to the sixth power?
geniusboy [140]

A) 6 x 6 x 6 x 6

Hope this Helps!!

3 0
4 years ago
Read 2 more answers
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
A pencil and an eraser cost € 1.40 (total cost).
Over [174]

Answer:

Eraser cost €0,2

Step-by-step explanation:

Cost of ereaser - x

Cost of pencil - x + 1

x + x + 1 = 1,4

2x + 1 = 1,4

2x = 0,4

x = 0,2

7 0
3 years ago
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