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Artemon [7]
3 years ago
12

Mixing hydroelectric acid and sodium hydroxide is an example of an exothermic reaction. If you were holding a beaker while this

chemical reaction took place, then you would except it to feel?
Chemistry
1 answer:
valentina_108 [34]3 years ago
8 0

Heat

Explanation:

if I hold a beaker during a reaction that is supposedly an exothermic reaction, I will feel that the heat of the beaker. In exothermic reaction, the environment becomes hotter at the end of the change.

  • Exothermic reaction is a type of enthalpy change.
  • In this kind of reaction, heat is liberated to the surroundings.
  • Here, the surrounding becomes hotter at the end of the changes.
  • Change in enthalpy is assigned a negative value as the sum of heat contents of products is less than that of the heat content of reactants.

Learn more:

Exothermic reaction brainly.com/question/10567109

#learnwithBrainly

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During a skin burn from an oven, approximate the skin and tissue layer to be infinitely thick compared to the damaged layer. The
Vlad [161]

Answer:

The depth of the damage is given as x   = 1.357*10^{-3}m

Explanation:

From Fick's second law

                 \frac{C_{x}-C_{0}}{C_{s}-C_{0}} = 1 -erf [\frac{x}{2\sqrt{Dt} } ] ...(1)

Where

 C_x is the temperature when the skin is damage

 C_0 is the initial temperature of the skin

  Cs is the temperature of the oven

 erf is a mathematical function known as error function

  D is the thermal diffusivity

 x is the depth of the damage

From the question we are given that

            C_x  = 62°C

           C_0   = 33°C

            D   =  2.5 * 10^{-7} m^2/s.

Substituting values into equation one

                    \frac{62-33}{200-33} = 1 -erf [\frac{x}{2\sqrt{2.5*10^{-7}} *2} ]

                  erf[\frac{x}{1.414*10^{-3}} ] = 0.826\\

       Let assume that  z =\frac{x}{1.414*10^{-3}} ...  (2)

Hence

           erf(z) = 0.826

Looking at the table of error function shown on the first uploaded image

 We can use interpolation to obtain the value of z in this manner

                  \frac{z-0.95}{0.8260-0.8209}  = 1        

                     z = 0.96

 Substituting the value of z into equation 2

           0.96 = \frac{x}{1.414*10^{-3}}

             x   = 1.357*10^{-3}m

               

 

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3 years ago
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