Law of Definite Proportions states that a compound is composed of the same ratio of elements present. The formation of water has a reaction:
H2 + 1/2 O2 = H2O
The limiting reactant would be the element with the least ratio of molar mass to stoichiometric coefficient, and that would be H2, not O2.
Answer:
Mass = 47.04 g
Volume = 23.94 L
Solution:
The equation for given reaction is as follow,
BaCO₃ + 2 HNO₃ → Ba(NO₃)₂ + CO₂ + H₂O
According to this equation,
197.34 g (1 mole) BaCO₃ produces = 44 g (1 mole) of CO₂
So,
211 g of BaCO₃ will produce = X g of CO₂
Solving for X,
X = (211 g × 44 g) ÷ 197.34 g
X = 47.04 g of CO₂
As we know,
44 g (1 mole) CO₂ at STP occupies = 22.4 L volume
So,
47.04 g of CO₂ will occupy = X L of Volume
Solving for X,
X = (47.04 g × 22.4 L) ÷ 44 g
X = 23.94 L Volume
Answer:
Correct option is
A
Explanation:
The number of molecules of CO involves in the slowest step will be 0 because CO is not involve in the slowest step i.e. rate determing step.
