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laiz [17]
3 years ago
12

Atoms in Group 18(8A) are inert (chemically unreactive) because

Chemistry
2 answers:
alexira [117]3 years ago
7 0

Answer:

ghghcgkhhgghhjkjhgffghjklpkjihuygf

Explanation:

Stolb23 [73]3 years ago
3 0

Answer: They combined to form molecules.

Explanation:

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Compound A, C12H22O, undergoes reaction with dilute H2SO4 at 50°C to yield a mixture of two alkenes, B and C, C12H20. The major
Nataly_w [17]

Answer:

Compound C is an alkene containing two cyclohexane rings attached with each other through a single bond.

Explanation:

  • Only cyclohexanone is obtained after ozonolysis of major alkene product. This means major alkene product, B , should contain contain two cyclohexane rings attached with each other through a double bond.
  • Compound B and C are obtained after dehyration of compound A by treating it with dilute H_{2}SO_{4} at 50^{0}\textrm{C}. So, compound A is an alcohol.
  • As compound B is obtained from compound A therefore compound A is an alcohol containing two cyclohexane rings attached with each other through a single bond.
  • Structures of all compounds are given below.

8 0
4 years ago
How is stoicheometry used to <br>keep camels alive​
Novay_Z [31]

Answer:

by heart beat camel lives

8 0
3 years ago
How many moles of H2 would be required to produce 37.0 moles of water?
svp [43]

Hii there !

The reaction accompanying production of water in this case would be -

\green{ \underline { \boxed{ \sf{H_2+ \frac{1}{2}O_2\longrightarrow H_2O}}}}

Thus ,by observing the reaction, we can conclude that 1 mole of Hydrogen (H_2)react with 1/2 mole of oxygen(O_2)to produce 1 mole of water (H_2O)

\impliesTherefore, 37.0 moles of hydrogen(H_2) will be required to produce 37.0 moles of water.

Hope it helps.

7 0
2 years ago
What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu
vladimir2022 [97]

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

3 0
3 years ago
Which order shows the size of the inner planets from smallest to largest
elixir [45]

Answer:

PLUTO

MERCURY

MARS

VENUS

EARTH

NEPTUNE

URANUS

SATURN

JUPITER

Explanation:

4 0
3 years ago
Read 2 more answers
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