All categories

3 years ago

{2.5x−3y=−13 3.25x−y=−14 how do i solve this

Mathematics

2 answers:

lara31 [8.8K]3 years ago

4 0

Answer:

(x=4.0 Y=1.0)

Step-by-step explanation:

Here you go

Kay [80]3 years ago

4 0

Answer:

(- 4, 1 )

Step-by-step explanation:

Given the 2 equations

2.5x - 3y = - 13 → (1)

3.25x - y = - 14 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate the term in y

- 9.75 + 3y = 42 → (3)

Add (1) and (3) term by term

- 7.25x = 29 ( divide both sides by - 7.25 )

x = - 4

Substitute x = - 4 in either of the 2 equations and solve for y

Substituting in (1)

- 10 - 3y = - 13 ( add 10 to both sides )

- 3y = - 3 ( divide both sides by - 3 )

y = 1

Solution is (- 4, 1 )

You might be interested in

12x+34>140 solve for x

Harlamova29_29 [7]

Answer:

x>\frac{53}{6}

Step-by-step explanation:

12x>140−34

2 Simplify 140-34140−34 to 106106.

12x>106

3 Divide both sides by 1212.

x>\frac{106}{12}

7 0

2 years ago

How much more did Isabel earn than Sarah?

N76 [4]

where's the storyy sisssssss

8 0

3 years ago

There are 44 students in a class.every student plays at least 1 of the 2 sports:baseball and soccer.27 students play baseball on

Anon25 [30]

The answer is 6 students.

6 0

3 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago

Given: AB with coordinates of AC-3, -1) and B(2, 1)

andrezito [222]

Answer:

up 2, right 3

Step-by-step explanation:

up 2, to the right 3.

8 0

3 years ago