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Wewaii [24]
3 years ago
14

Which quadrilateral always has two pairs of parallel sides, four right angles, and four congruent sides?

Mathematics
1 answer:
AlekseyPX3 years ago
6 0
The answer is b a square.
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How to write a polynomial function with rational coefficients in standard form with the given zeros?
Gennadij [26K]
If you have as many zeros (z1, z2,... zn) as the degree of the polynomial function (n), then the function equation is given by:

f(x) = k (x - z1) (x - z2) ··· (x - zn)

where k is a constant. To determine this constant you need additional information (e.g. another point of the function).

You might also have less zeros than the degree of the polynomial, because some of them have a multiplicity greater than 1. Let z1,...,zr be the zeros, and m1,...mr be the multiplicity of each zero, where m1+m2+...+mr=n (we assume the sum of all multiplicities equals the degree of the polynomial). In this case, you can use:

f(x)=k(x-z_1)^{m_1} (x-z_2)^{m_2} \cdots (x-z_r)^{m_r}

Again, you have an undetermined constant factor.

From any of the two expressions above, you have to apply the distributive property to go on to the standard form.

An example: the zeros of a 3-degree polynomial function are -2, 1 and 3. The function equation is of this form:

f(x)=k(x+2)(x-1)(x-3) = k(x^3-2x^2-5x+6)

If you don't have all the zeros, or the sum of multiplicities does not equal the degree of  the polynomial, you have not enough information to write the equation of the function.

4 0
3 years ago
A+4<9 solve the inequality
Nata [24]

Answer:

A < 5

Step-by-step explanation:

Move 4 to other side to isolate for x

A < 9-4

A < 5

6 0
3 years ago
a trapezoid has base lengths of (6x-1) units and 3 units. Its midsegment has a length of (5x-3) units. What is the value of x?
vodka [1.7K]
1. You have that:

 - The<span> lengths of the bases are (6x-1) units and 3 units.
 - The midsegment has a length of (5x-3) units.

 2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:

 Midsegment=Base1+Base2/2

 As you can see, the midsegment is half the sum of the bases of the trapezoid.

 3. When you substitute the values, you obtain:

 (5x-3)=[(6x-1)+3]/2

 4. Now, you can solve the problem by clearing the "x":
</span>
 (5x-3)=[(6x-1)+3]/2
 2(5x-3)=6x-1+3
 10x-6=6x+2
 10x-6x=2+6
 4x=8
 x=8/4
 x=2
3 0
3 years ago
Can someone help me please? It’s has to be using the system elimination!
Natalka [10]

The answer is within the file provided.

Download pdf
3 0
3 years ago
How do you do this problem 2n^3-n^2-136n=0
Rzqust [24]
<span>2n^3-n^2-136   :Equation: 

                                      Substitute 0 for n  

</span>                                      Simplify {20}^{3}<span> to </span><span>8000 
</span>
<span>8000−<span>0<span><span>​^2</span><span>​​</span></span></span>−136 

</span>                                     Simplify <span>{0}^{2}<span>​​</span></span><span> to </span><span>0 
</span><span><span>8000−0−136 

= 7864</span></span><span>
</span>
5 0
3 years ago
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