Answer:
![A_w=8x+336](https://tex.z-dn.net/?f=A_w%3D8x%2B336)
Step-by-step explanation:
From the question we are told that:
Length of pool ![l_p=34](https://tex.z-dn.net/?f=l_p%3D34)
width of pool ![w_p=x](https://tex.z-dn.net/?f=w_p%3Dx)
Width of brick-walk way
Generally the equation for Area of the pool
is mathematically given by
![A_p=l_p*w_p\\\\A_p=34*x](https://tex.z-dn.net/?f=A_p%3Dl_p%2Aw_p%5C%5C%5C%5CA_p%3D34%2Ax)
Generally the equation for Area of the pool with its walkway
is mathematically given by
![A_w'=l_w'+w_w'\\\\A_w'=l_w'+w_w'](https://tex.z-dn.net/?f=A_w%27%3Dl_w%27%2Bw_w%27%5C%5C%5C%5CA_w%27%3Dl_w%27%2Bw_w%27)
Where
![l_w'=length\ of\ pool\ with\ walkway\\\\l_w'=l_p+4+4\\\\l_w'=34+4+4\\\\l_w'=42](https://tex.z-dn.net/?f=l_w%27%3Dlength%5C%20of%5C%20pool%5C%20with%5C%20walkway%5C%5C%5C%5Cl_w%27%3Dl_p%2B4%2B4%5C%5C%5C%5Cl_w%27%3D34%2B4%2B4%5C%5C%5C%5Cl_w%27%3D42)
Therefore
![w_w'=width\ of\ pool\ with walkway\\\\w_w'=w_p+8\\\\A_w'=42*(x+8)](https://tex.z-dn.net/?f=w_w%27%3Dwidth%5C%20of%5C%20pool%5C%20with%20walkway%5C%5C%5C%5Cw_w%27%3Dw_p%2B8%5C%5C%5C%5CA_w%27%3D42%2A%28x%2B8%29)
Generally the equation for pool's walkway
is mathematically given by
![A_w=A_w'-A_p\\\\A_w=(42*(x+8))-(34x)](https://tex.z-dn.net/?f=A_w%3DA_w%27-A_p%5C%5C%5C%5CA_w%3D%2842%2A%28x%2B8%29%29-%2834x%29)
![A_w=8x+336](https://tex.z-dn.net/?f=A_w%3D8x%2B336)
- Slope-Intercept Form: y = mx+b, with m = slope/rate of change and b = y-intercept.
So for this to be slope-intercept form, we first have to divide both sides by 2: ![y=\frac{5}{2}x+5](https://tex.z-dn.net/?f=%20y%3D%5Cfrac%7B5%7D%7B2%7Dx%2B5%20)
Now that it's slope-intercept form, we see that <u>the rate of change is 5/2, or 2.5.</u>
Answer:
A: 4/8
Step-by-step explanation:
1/2 is the same as 4/8 because if we divide 4 to both the numerator (4 divided by 4) and the denominator (8 divided by 2), we get 1 for the numerator and 2 for the denominator.
Answer:
Option A. x + 3
Step-by-step explanation:
From the question given above, the following data were obtained:
Area (A) = x² + 2x – 3
Width (W) = x – 1
Lenght (L) =?
The area of a rectangle is given by:
Area (A) = length (L) × Width (W)
A = L × W
With the above formula, we can obtain the lenght of the rectangle as follow:
Area (A) = x² + 2x – 3
Width (W) = x – 1
Lenght (L) =?
A = L × W
(x² + 2x – 3) = L(x – 1)
Divide both side by (x – 1)
L = (x² + 2x – 3) / (x – 1)
Please see attached photo for explanation
L = x + 3
Thus, the length of the rectangle is x + 3
Answer:
A. 14%.
B. ![\frac{43}{50}](https://tex.z-dn.net/?f=%5Cfrac%7B43%7D%7B50%7D)
Step-by-step explanation:
We have been given that a running back was the MVP (most valuable player) in 0.14 of the first 50 Super Bowls.
A. To find the percent, when the MVPs were running backs, we need to convert 0.14 into percent by multiplying by 100 as:
![0.14\times 100=14\%](https://tex.z-dn.net/?f=0.14%5Ctimes%20100%3D14%5C%25)
Therefore, 14 percent of the MVPs were running backs.
B. To find the fraction of the MVPs were not running backs, we will subtract 0.14 from 1 to find the MVPs, who were not running backs. Finally, we will convert the answer into fraction as:
![1-0.14=0.86](https://tex.z-dn.net/?f=1-0.14%3D0.86)
Now, we will multiply and divide 0.86 by 100 as:
![0.86\times \frac{100}{100}=\frac{86}{100}](https://tex.z-dn.net/?f=0.86%5Ctimes%20%5Cfrac%7B100%7D%7B100%7D%3D%5Cfrac%7B86%7D%7B100%7D)
Reduce the fraction by dividing numerator and denominator by 2:
![\frac{43}{50}](https://tex.z-dn.net/?f=%5Cfrac%7B43%7D%7B50%7D)
Therefore,
of the MVPs were not running backs.