a trapezoid has base lengths of (6x-1) units and 3 units. Its midsegment has a length of (5x-3) units. What is the value of x?
1 answer:
1. You have that:
- The<span> lengths of the bases are (6x-1) units and 3 units.
- The midsegment has a length of (5x-3) units.
2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:
Midsegment=Base1+Base2/2
As you can see, the midsegment is half the sum of the bases of the trapezoid.
3. When you substitute the values, you obtain:
(5x-3)=[(6x-1)+3]/2
4. Now, you can solve the problem by clearing the "x":
</span>
(5x-3)=[(6x-1)+3]/2
2(5x-3)=6x-1+3
10x-6=6x+2
10x-6x=2+6
4x=8
x=8/4
x=2
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The answer should be 43
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Step-by-step explanation:
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25 = -16t^2 + 50t + 4
16t^2 - 50t + 21 = 0
16t^2 - 8t - 42t + 21 = 0
8t(2t - 1) - 21(2t - 1) = 0
(8t - 21)(2t - 1) = 0
8t - 21 = 0 or 2t - 1 = 0
t = 21/8 or t = 1/2
t = 2.625 or t = 0.5
2.) 15+45 = 60
3.) 9+27 = 36
Answer:
c=93
Step-by-step explanation:
35+3(x+2)+52=180
87+3(x+2)=180
87+3x+6=180
93+3x=180
3x=180-93
3x=87
x=87/3
x=29
3(29+2)
3(31)=93
