3 years ago

Help ASAP

Mathematics

1 answer:

Hoochie [10]3 years ago

5 0

Don’t at me I think it’s B

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What is the solution set of (3x - 1)^2 = 5?<br><br><br> HEEEELLLLLLLLLLLPPPPPPPPP

babunello [35]

*I'll be keeping the solutions in exact form*

So firstly, square root both sides. This will split the equation into two:

$3x-1=\sqrt{5} \\ 3x-1=-\sqrt{5}$

Next, add 1 on each side: $3x=\sqrt{5}+1 \\ 3x=-\sqrt{5}+1$

Next, divide 3 on both sides, and your answers will be $x=\frac{\sqrt{5}+1}{3},\frac{-\sqrt{5}+1}{3}$

3 0

3 years ago

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Mumz [18]

Answer:

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7 0

2 years ago

Please help i need the anwser for only those two also those are the anwsers for both IM MARKING BRAINIEST

qwelly [4]

Answer:

1) 22.93

2) 72/ 2π

Step-by-step explanation:

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3 years ago

Which expression is equivalent to the given expression?

bixtya [17]

Expression is equivalent to the given expression 13x−29xthat could be simplified by just substracting it13x − 29x = -16x but it is not in the choices
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4 years ago

Consider the given function and the given interval. f$x$ = (x - 7)**2 text(, ) [5 text(, ) 11] (a) Find the average value fave

Jet001 [13]

a. $f$ has an average value on [5, 11] of

$f_{\rm ave}=\displaystyle\frac1{11-5}\int_5^{11}(x-7)^2\,\mathrm dx=\frac{(x-7)^3}{18}\bigg|_5^{11}=\frac{4^3-(-2)^3}{18}=4$

b. The mean value theorem guarantees the existence of $c\in(5,11)$ such that $f(c)=f_{\rm ave}$ . This happens for

$(c-7)^2=4\implies c-7=\pm2\implies c=9\text{ or }c=5$

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4 years ago