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EastWind [94]
3 years ago
11

How many dimes and quarters are in 4.80

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer: There are 18 quarters and 3 dimes in $4.80

Step-by-step explanation:

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Can you form a triangle with these given side lengths? 12 , 8 , 16<br><br> Please help me!!!!
Scilla [17]

Answer:

yes

Step-by-step explanation:

12+8>16

the two short sides have to be greater than the longest dude when combined and that is true so you can form a triangle

6 0
3 years ago
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Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o
umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that  

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So  

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now  

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)  

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)  

1/2 ∫▒(2xdx/u) =1/2  ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2  ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C  (required soultion)

3 0
3 years ago
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Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:
agasfer [191]

Answer:12533

Step-by-step explanation:

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I=$26.25I=$26.25, P=$500P=$500, t=18 t=18 months
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What is the acutal question
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Evaluate: 23 + x/8 for x = 8
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23 + x/8

substitute 8 in x

23 + 8/8

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