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evablogger [386]
4 years ago
7

Activity 4 | Solve the missing piece

Physics
1 answer:
Soloha48 [4]4 years ago
7 0

Answer:

<u>69</u>

Explanation:

4376

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What muscle movement do we use to close a joint.
marin [14]

Answer: Your using your skeletal muscle

Explanation:

3 0
3 years ago
What is a controlled experiment? A.An experiment with only experimental variables B.An experiment with one dependent variable an
horrorfan [7]
I am pretty sure its B i hope i helped ;p but sry if i got u wrong
7 0
3 years ago
Current Attempt in Progress The atomic radii of a divalent cation and a monovalent anion are 0.52 nm and 0.125 nm, respectively.
Mnenie [13.5K]

Answer:

a)   F = 1.70 10⁻⁹N,   F = 1.47 10⁻⁸ N,

b) * the electronegative repulsion, from the repulsion by quantum effects

Explanation:

a) The atraicione force comes from the electric force given by Coulomb's law,

           F = k \frac{ q_1 q_2}{r^2}

divalent atoms

In this case q = 2q₀ where qo is the charge of the electron -1,6 10⁻¹⁹ C and the separation is given

           F = k q² / r²

           F = 2 \ 10^9 \  \frac{2 (1.6 \  10^{-19} )^2}{ (0.52 10^{-9} )^2 }

           F = 1.70 10⁻⁹N

monovalent atoms

in this case the load is q = q₀

           F = 2 \ 10^9 \  \frac{ (1.6 \  10^{-19} )^2}{ (0.125 10^{-9} )^2 }

           F = 1.47 10⁻⁸ N

b) repulsive forces come from various sources

* the electronegative repulsion of positive nuclei

* the electrostatic repulsion of the electrons when it comes to bringing the electron clouds closer together

* from the repulsion of electron clouds, by quantum effects

8 0
3 years ago
What is the intensity of the electromagnetic light waves coming from the Sun just outside of the atmosphere of Venus, Earth and
Firdavs [7]

The sun emits electromagnetic waves with a power of  

4.0 ∗ 10  (26)  W.

6 0
3 years ago
If a snowball melts so that its surface area decreases at a rate of 10 cm2/min, find the rate at which the diameter decreases wh
liubo4ka [24]

Answer: 4/9π

Explanation:

Surfacearea of snowball(SA) =4πr^2

dSA/dT = - 10cm^2/min

d = 9, hence, r = 9/2 = 4.5

Taking the derivative of surface area with respect to time:

dSA/dT = 8πrdr/dt

dSA/dT = - 10, r = 4.5

-10 = 8π(4.5)dr/dt

-10 = 36πdr/dt

Make dr/dt subject of the formula

dr/dt = - 10/36π

d = 2r

Differentiating d with respect to time, 't'

dd/dt = 2dr/dt

Therefore, 2dr/dt = 2*(dr/dt)

2×(- 10/36π) = - 20/36π

= -4/9π

Therefore, rate by which diameter decreases when diameter is 9cm is

4/9 π

7 0
3 years ago
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