Answer:
they are both played by hoomans
The closure temperature represents the point when isotopes are no longer free to move out of a crystal lattice.
Answer: Option C
<u>Explanation:</u>
The closure temperature can also be termed as blocking temperature. It is mostly used in radiometric dating. As the temperature decreases, below a certain point the isotopes may get freeze in their lattice positions. And there may be slowing of diffusion.
At the closure temperature, that rate of diffusion will be zero as the isotopes will be no longer free to move out of crystal lattice. So, this is termed as closure or blocking temperature. As the isotopes loose their ability to move, their concentration will remain fixed in their position leading to measurement of radiation dating.
Answer: e. on the equator and in the Atlantic Ocean
Explanation:
Latitude and Longitude are geographical coordinates.
<u>Latitude</u> is the angular distance between the <u>equatorial line</u>, and a specific point on the Earth. It is measured in degrees and is represented according to the hemisphere in which the point is located, which can be north or south latitude.
In this sense latitude 
refers to the equatorial line that divides the Earth in two hemispheres (North and South).
On the other hand, <u>Longitude</u> represents the specific <u>east–west </u>position of a point on the Earth's surface, being longitude the prime meridian or Greenwich meridian.
So, if we have latitude and longitude 
(positive means it is to the East) we can already know the point is in the equator, and the option that bests describes the coordinates is e.
The spine is the one that keeps a huminss body mantaned
Answer:
a ) 540 ft /s
b ) .144° /s
Explanation:
Let at any moment h be the height of the rocket . The distance of rocket from camera will be R
R ² = 4000² + h²
Differentiating both sides with respect to t
R dR/dt = h dh/dt
dR/dt = h/R dh/dt
a ) Given speed of rocket
dh/dt = 900
h = 3000
R² = 4000² + 3000²
R = 5000
dR/dt = h/R dh/dt
= (3000 / 5000 ) X 900
dR/dt = 540 ft /s
b ) Let θ be angle of elevation at the moment .
4000 / R = cosθ
Differentiating with respect to t
- 4000 x 1 / R² dR/dt = - sinθ dθ / dt
4000 x ( 1/ 5000² ) x 540 = 3 /5 x dθ / dt
.0864 = 3/5 dθ / dt
dθ / dt = .144° /s
