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3 years ago

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Which statement best compares and contrasts two physical properties of natter

1 answer:

Citrus2011 [14]3 years ago

6 0

Answer:

D.

Explanation:

There are three physical properties of matter that involves solid, liquid and gas.

The last statement is correct as it says: boiling and melting points are similar as both changes the physical state of matter. But are different as boiling point changes liquid into gas for example: liquid at high boiling point changes into vapors (gas) and melting point changes solid into liquid for example: ice at high melting point changes into liquid.

Hence, the correct option is "D".

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High-speed stroboscopic photographs show that the head of a 180 g golf club is traveling at 47 m/s just before it strikes a 46 g

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Answer:

47 m/s

Explanation:

golf club mass, mc = 180 g

golf ball mass, mb = 46 g

initial golf club speed, vc1 = 47 m/s

final golf club speed, vc2 = 35 m/s

initial golf ball speed, vb1 = 0 m/s

final golf ball speed, vb2 = ? m/s

The total momentum is conserved, then:

mc*vc1 + mb*vb1 = mc*vc2 + mb*vb2

Replacing with data and solving (dimension are omitted):

180*47 + 46*0 = 180*35 + 46*vb2

vb2 = (180*47 - 180*35)/46

vb2 = 47 m/s

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Four forces act on a hot-air balloon, as shown

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The magnitude of the resultant force on the balloon is 374.13 N.

The given forces from the image;

<em>Upward force = 514 N</em>
<em>Downward force = 267 N</em>
<em>Eastward force = 678 N</em>
<em>Westward force = 397 N</em>

The net vertical force on the balloon is calculated as follows;

$F_y = 514 \ N \ \ - \ \ 267 \ N\\\\F_y = 247 \ N$

The net horizontal force on the balloon is calculated as follows;

$F_x = 678 \ N \ - \ 397 \ N\\\\F_x = 281 \ N$

The magnitude of the resultant force on the balloon is calculated as follows;

$F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(247)^2 + (281)^2} \\\\F= 374.13 \ N$

Thus, the magnitude of the resultant force on the balloon is 374.13 N.

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