Answer:
ΔT = 13.65° C
ΔQ = 13.7 J
Explanation:
First we will find the final temperature of air by using equation of state:
P₁V₁/T₁ = P₂V₂/T₂
For Isochoric Process, V₁ = V₂
Therefore,
P₁/T₁ = P₂/T₂
T₂ = P₂T₁/P₁
where,
T₂ = Final Temperature = ?
P₂ = Final Pressure = 1050 mb
P₁ = Initial Temperature = 1000 mb
T₁ = Initial Temperature = 0°C = 273 k
Therefore,
T₂ = (1050 mb)(273 K)/(1000 mb)
T₂ = 286.65 K
Change in Temperature = ΔT = T₂ - T₁
ΔT = 286.65 K - 273 K
<u>ΔT = 13.65° C</u>
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The first law of thermodynamics can be written as:
ΔQ = ΔU + W
where,
ΔQ = heat absorbed
ΔU = change in internal energy = mCΔT
W = Work Done = 0 (in case of isochoric process)
Therefore.
ΔQ = mCΔT
where,
m = mass of air = 1 g = 1 x 10⁻³ kg
C = specific heat of dry air = 1003.5 J/kg.°C
Therefore,
ΔQ = (1 x 10⁻³ kg)(1003.5 J/kg.°C)(13.65°C)
<u>ΔQ = 13.7 J</u>
Answer:
v = 9.07 m/s
the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s
Explanation:
Given;
An eagle is flying horizontally at a speed of 4.6 m/s
Initial horizontal velocity uh = 4.6 m/s
Initial vertical velocity uy = 0
Height to fall d = 4.2 m
Acceleration due to gravity g = 9.8 m/s^2
The final vertical velocity of the fish when it hits the water can be calculated using the equation of motion;
v^2 = u^2 + 2as
v^2 = uy^2 + 2gd
uy = 0
v^2 = 2gd
v = √(2gd)
Substituting the given values;
v = √(2×9.8×4.2)
v = 9.073036977771 m/s
v = 9.07 m/s
the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s
Work= F times d so force x distance
25(.5) is 12.5
It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
Answer:
A. Its unique strength allows predetermined engineering stresses to be placed in members to counteract stresses that occur when the unit is subjected to service loads
Explanation:
Prestressed concrete is a structural material that allows for predetermined, engineering stresses to be placed in members to counteract the stresses that occur when they are subject to loading.
It combines the high strength compressive properties of concrete with the high tensile strength of steel.
‘Building Construction Handbook’ (6th ed.), CHUDLEY, R., GREENO, R., Butterworth-Heinemann (2007)
Then the correct answer is:
A. Its unique strength allows predetermined engineering stresses to be placed in members to counteract stresses that occur when the unit is subjected to service loads
