Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:

1/16 CCWW (lethal)

2/16 CCWw (white)

2/16 CcWW (lethal)

4/16 CcWw (white)

1/16 CCww (normal)

2/16 Ccww (normal)

2/16 ccWw (albino)

1/16 ccWW (lethal)

1/16 ccww (albino)

Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.

8 0

3 years ago

Select the correct answer from the drop-down menu.

Archy [21]

-2,-2 I think that’s the answer

5 0

3 years ago

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What is the value of x in the equation −x = 4 − 3x + 6? A. 5 B. 10 C. −5 D. −10

Ann [662]

$-x = 4-3x+6$

Refine $4-3x + 6$

$-3x = 4+6$

$-3x = 10$

Add $3x$ to both sides:

$-x + 3x = -3x + 10 + 3x$

$2x = 10$

Divide both sides by 2 :

$\frac{2x}{2} = \frac{10}{5}$

$x = 5$

Answer a

hope this helps!

8 0

3 years ago

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Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card. What is the probability that

professor190 [17]

Answer:

Therefore, the probability is P=3/32.

Step-by-step explanation:

We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.

We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.

The probability that he pulls out a 3 first is 3/8.

The probability of a second card being 2 is 2/8.

We get:

$P=\frac{3}{8}\cdot \frac{2}{8}\\\\P=\frac{6}{64}\\\\P=\frac{3}{32}$

Therefore, the probability is P=3/32.

7 0

3 years ago