6, 7, 8, and 9. just plug the X into the equation
Answer:
Step-by-step explanation:
a1=2/3
sequence is 2/3,3/4,4/5,...
for numerator a1=2
d=3-2=1
numerator of nth term=a1+(n-1)d=2+(n-1)×1=2+n-1=n+1
denominator = 1 more than numerator=n+1+1=n+2
so an=(n+1)/(n+2)
or for denominator a1=3,d=4-3=1
denominator of nth term=3+(n-1)×1=3+n-1=n+2
an=(n+1)/(n+2)
Answer and explanation:
Please find attached answer and explanation
Answer:
width = 2 units
Step-by-step explanation:
If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.
the area of a rectangle is length * width
so just substitute the values that we have now.
x (length) * (x-4) width = 12 (area of rectangle)
so that gives us
x^2 - 4x =12
subtract 12 from both sides
x^2 - 4x - 12 =0
now factor this equation
x^2 + 2x - 6x -12 = 0
x(x+2) - 6(x+2) = 0
(x-6)(x+2) = 0
x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE
length = 6, and width = 6 -4 = 2
Answer:
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
Step-by-step explanation:
Given that;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
cumulative distribution function can be calculated by; be cumulatively up the value of p(x) with the values before it;
so
x F(x)
0 P(X = 0) = 0.17
1 P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4
2 P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65
3 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91
4 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1
Therefore, cumulative distribution function f(x) is;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
