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3 years ago

What is the value of x? Enter your answer in the box. °

Mathematics

2 answers:

lapo4ka [179]3 years ago

6 0

Answer:

how are we supposed to answer this question when there isn't a picture or anything

Step-by-step explanation:

Fynjy0 [20]3 years ago

5 0

38 pudupdlhduodupslhdgoshoxgodlhdhldohdoyd

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-2(6+s)>-15-2s<br><br> Please answer!!

valkas [14]

This problem has infinitly many solutions

6 0

3 years ago

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What property is illustrated in the identity shown below?<br> 2(3x+1)=6x+2

Paha777 [63]

It’s a infinite because do fist 2•3x= 6x then 2•1=2 then look 6x+2=6x+2

8 0

3 years ago

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Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago

at the city museum child admission is $5.10 and adult admission is $9.60. on thursday 132 tickets were sold for a total sale of

Bad White [126]

C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20

5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold

5 0

3 years ago

Solve1 over 25 = 5^x ^+ 4. <br> x = -7/2<br> x = −6 <br> x = 9/2 <br> x = 2

Basile [38]

The equation seems to be

   1
-------- = 5 ^ (x + 4)
25

In that case, this is the solution, stept by step:

1) factor 25: 25 = 5^2

      1
=> ----------- = 5^(x + 4)
       5^2

2) invert 5^2

=> 5^(-2) = 5^(x+4)

3) Given that the bases are equal, the exponents also have to be equal:

=> - 2 = x + 4

3) transpose +4:

=> - 2 - 4 = x

=> x = - 6

Answer: - 6

6 0

3 years ago