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3 years ago

Find the missing length for a right triangle with hypotenuse of 18 and a leg length of 6

Mathematics

2 answers:

Alla [95]3 years ago

8 0

16.9705624748447714
if you want it rounded its 16.97 or 16.9
thanks for letting me answer and god bless <3

yaroslaw [1]3 years ago

4 0

$\sqrt{18^2-6^2}$
$\sqrt{256-36} = \sqrt{220} = 2 \sqrt{55}$

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MrMuchimi

Answer:

220 i think but im not sure

Step-by-step explanation:

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SpyIntel [72]

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3 years ago

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o-na [289]

Answer:

$\large\boxed{x=4\pm2\sqrt6}$

Step-by-step explanation:

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2 years ago

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Helen [10]

Answer:

90/23

Step-by-step explanation:

First, you want to start in the parentheses. 5-6=-1, then multiply it by -2. Since a negative multiplied by a negative is a positive, -2*-1=2. -3^2=-9. 2+8=10. Then -9 times 10= -90. Then, we move on to the bottom. 5--2=7. 4^2=16, and -2(2)=-4. So -5(7) + 16-4=-23. Now, the equation should look like this, -90/-23. Put the negatives together and you get 90/23.

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3 years ago

1. How can you find the decimal forms of 3/12 and 2/9?

Helga [31]

Answer:

1. 0.472

2. 0.25

Step-by-step explanation:

1. reduce the fraction with 3 = 1\4 + 2\9

write all numerators above the Least common denominator 36 =9 + 8\36

Add numbers = 17\36 and the alternate form is 0.472

2. Divide the numerator and denominator by three = 3 ÷ 3\12 ÷ 3 = 0.25

I can't do the others now I have an exam(sorry)

6 0

2 years ago