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larisa [96]
3 years ago
14

What is 40 x 365 / 6

Mathematics
2 answers:
Semmy [17]3 years ago
5 0

Answer:

1,4600

Step-by-step explanation:

GalinKa [24]3 years ago
4 0

Answer: 2433.3333333

Step-by-step explanation:

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Solve F(x) for the given domain. <br> F(x) = x ^2 + 3x - 2 <br> F(3) = <br> 13<br> 16<br> 40
olchik [2.2K]
F(3) = 16, you simply plug in 3 for x to find the answer.
6 0
3 years ago
49÷369 explain answer
Afina-wow [57]

49 divided by 369 is 0.13279133 and 369 divided by 49 is 7.53061224

5 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
The table below shows some inputs and outputs of the invertible function f with domain all real numbers.
Ratling [72]

Answer:

{f}^{ - 1} (f(93)) = 93

f(f(7)) =  - 15

Step-by-step explanation:

A function and its inverse has the following properties

{f}^{ - 1} (f(x)) = x

This implies that;

{f}^{ - 1} (f(93)) = 93

From the table,

f(7) =  - 6

This means that:

f(f(7)) = f( - 6)

f(f(7)) =  - 15

Note that: f(7) means the value of f(x) when x=7.

From the table f(x)=-6 when x=7.

That is why f(7)=-6.

5 0
3 years ago
HELP ASAP!!!
artcher [175]
The answer will be d but I am not fully sure.
8 0
2 years ago
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