Question

The function F is defined by F(x)= 12/x + 1/2 . Use this formula to find the following values of the function.

Answer 1

Answer:

$F(3)=\frac{9}{2} \\F(-12)=\frac{-1}{2} \\F(\frac{1}{3} )=\frac{73}{2} \\F(\frac{3}{4} )=\frac{33}{2}$

Step-by-step explanation:

Given: $F(x)= \frac{12}{x} + \frac{1}{2}$

To find: Values of the function F(3) , F(−12) , $F(\frac{1}{3})$, $F(\frac{3}{4})$

Solution:

A function is a relation in which each and every element of the domain has a unique image in the co-domain.

To find the values of the functions $F(3),F(-12),F(\frac{1}{3} ),F(\frac{3}{4} )$, put $x=3, -12, \frac{1}{3},\frac{3}{4}$ in the given function $F(x)= \frac{12}{x} + \frac{1}{2}$

$F(x)= \frac{12}{x} + \frac{1}{2}\\F(3)= \frac{12}{3} + \frac{1}{2}\\=4 + \frac{1}{2}\\=\frac{9}{2}$

$F(x)= \frac{12}{x} + \frac{1}{2}\\F(-12)= \frac{12}{-12} + \frac{1}{2}\\=-1+\frac{1}{2}\\ =\frac{-1}{2}$

$F(x)= \frac{12}{x} + \frac{1}{2}\\\\F(\frac{1}{3} )= \frac{12}{\frac{1}{3}} + \frac{1}{2}\\=36+\frac{1}{2}\\ =\frac{73}{2}$

$F(x)= \frac{12}{x} + \frac{1}{2}\\\\\\F(\frac{3}{4} )= \frac{12}{\frac{3}{4}} + \frac{1}{2}\\\\=16+\frac{1}{2}\\ \\=\frac{33}{2}$

Answer 2

Answer:

Step-by-step explanation:

Substitute in each value for x: F(x) becomes F(3)=12/3+1/2=2