Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
Hi!
Let's take a look at the equation:
F = C + 32
What do we notice?
C and F are both variables.
Variables are unknown numbers represented by a letter.
In this case, C and F are the variables.
Hope this helps!
- Melanie
Answer: 2.4 years or 28.8 months
Then it would be 10-5 < 7
so if you solved it it would be 5 < 7
So this statement is true